Question

6 minutes ago • Chemistry • High School

Answer 1

Answer:

387.62, 83.33%

Explanation:

Given:

$C_{12} H_{22} O_{11}(aq) + H_2O(g) -4 C_2H_5OH(1) + 4 CO_2(g)$

720g of Sucrose produces 323g ethanol.

Theoretical yield

To calculate the theoretical yield, you can use a mole-to-mole ratio. Assuming that there is excess H2O, you can calculate the theoretical yield like so:

$720g C_{12}H_{22}O_{11}*\frac{1 mol C_{12}H_{22}O_{11}}{342.3g} *\frac{4mol C_2H_5OH}{1mol C_{12}H_{22}O_{11}} *\frac{46.07g}{1molC_2H_5OH} =387.62g$

Percent Yield

An easy way to find percent yield is

$\frac{Actual }{Theoretical} *100$

So, plug the numbers in.

$\frac{323.0}{387.62} *100 = 83.33%$

So, the percent yield is 83.33%.