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Mrrafil [7]
3 years ago
6

Which is an example of what should be done in case of a laboratory accident? Wear appropriate lab attire. Read directions comple

tely. Do not try to clean up a spill. Remain in the area.
Chemistry
2 answers:
Sauron [17]3 years ago
8 0

Answer:

C

Explanation:

I just took the quiz trust me

riadik2000 [5.3K]3 years ago
6 0

Answer: C. Do not try to clean up a spill.

Explanation:

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Which of the following hypotheses cannot be tested using the scientific method
Arturiano [62]
I believe it's answer #3. Logically, at least.

You can test #1 through trial and error.
You can experiment #2 also through trial and error.
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Pani-rosa [81]

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3 years ago
Estimate ΔH for the reaction: C2H6(g) + Cl2(g)--> C2H5Cl(g) + HCl(g) given the following average bond energies (in kJ/mol): C
Leno4ka [110]

Explanation:

The reaction equation will be as follows.

    C_{2}H_{6}(g) + Cl_{2}(g) \rightarrow C_{2}H_{5}Cl(g) + HCl(g)

Using bond energies, expression for calculating the value of \Delta H is as follows.

    \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

On reactant side, from C_{2}H_{6} number of bonds are as follows.

C-C bonds = 1

C-H bonds = 6

From Cl_{2}; Cl-Cl bonds = 1

On product side, from C_{2}H_{5}Cl number of bonds are as follows.

C-C bonds = 1

C-H bonds = 5

C-Cl bonds = 1

From HCl; H-Cl bonds = 1

Hence, using the bond energies we will calculate the enthalpy of reaction as follows.

  \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

  =[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]            = -102 kJ/mol

Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.

5 0
3 years ago
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