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3 years ago

6

Which is an example of what should be done in case of a laboratory accident? Wear appropriate lab attire. Read directions comple

tely. Do not try to clean up a spill. Remain in the area.

2 answers:

Sauron [17]3 years ago

8 0

Answer:

C

Explanation:

I just took the quiz trust me

riadik2000 [5.3K]3 years ago

6 0

Answer: C. Do not try to clean up a spill.

Explanation:

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What is the mass number, symbol, and charge of an atom that contains 19 protons, 20 neutrons and 19 electrons?

Crazy boy [7]

Answer:

Explanation:

mass number = 19 + 20 = 39 (protons + neutrons)

The charge is 0. This is an atom

The symbol = K

Protons: 19

Electrons: 19

Neutrons: 20

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3 years ago

Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution of hydr

xxTIMURxx [149]

Answer:

0.374 g

Explanation:

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Since both the molarity and the volume allows us to know the moles of potassium permanganate, and we already have the balanced chemical reaction, the stoichiometric procedure that is attached in the picture, is developed to substantiate the the titrated mass of hydrogen peroxide was 0.374 g.

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3 years ago

Graph the circle which is centered at (4,4)(4,4)left parenthesis, 4, comma, 4, right parenthesis and has a radius of 3 units.

OleMash [197]

Answer:

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3 years ago

PLEASE SOMEONE! The density of the acetic acid solution is 1.05 g/mL. Calculate the %(m/m) of the acetic acid solution (convert

tigry1 [53]

Answer:

The Percentage concentration of acetic acid = 1.39 %

Explanation:

Density of acetic acid solution = 1.05 g/mL

Volume of acetic acid solution = 0.1 L = 100 mL

From the formula, Density = mass / volume; mass = density × volume

Mass of acetic acid solution = 1.05 g/mL × 100 mL = 105 g

Molar concentration of acetic acid solution = 0.243 mol/L

Molar mass of acetic acid, CH₃COOH = (12 × 2 + 1 ×4 + 16 ×2) = 60 g/mol

From the formula, mass concentration = molar concentration × molar mass

Mass concentration of acetic acid, CH₃COOH = 0.243 mol/L × 60 g/mol = 14.58 g/L

In one liter of acetic acid solution, there are 14.58 g of acetic acid. Therefore, in 0.1 L, there will be 14.58 × 0.1 = 1.458 g of acetic acid.

Percentage concentration of acetic acid = mass of acetic acid / mass of acetic acid solution × 100%

Percentage concentration of acetic acid = (1.458 / 105) × 100% = 1.39 %

The Percentage concentration of acetic acid = 1.39 %

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2 years ago

How do you find the volume of a liquid

mart [117]

Today they will practice measuring different liquids. They will use a container called a graduated cylinder to measure liquids. Graduated cylinders have numbers on the side that help you determine the volume. Volume is measured in units called liters or fractions of liters called milliliters (ml).

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3 years ago