Answer:
x2=0.732m
Explanation:
We can calculate the spring constant using the equilibrium equation of the block m1. Since the spring is in equilibrium, we can say that the acceleration of the block is equal to zero. So, its equilibrium equation is:

Then using the equilibrium equation of the block m2, we have:

In words, the lenght x2 of the spring when the m2 block is hung from it, is 0.732m.
The best way to treat CO poisoning is to breathe in pure oxygen. This treatment increases oxygen levels in the blood and helps to remove CO from the blood. Your doctor will place an oxygen mask over your nose and mouth and ask you to inhale.
Is that what you mean? Treat the poisoning? It’s a gas, so you can dispose of the gas. Unless you mean dispose of the detector?
Answer:
Kinetic energy of the projectile at the vertex of the trajectory:
.
Work done when firing this projectile:
.
Explanation:
Since the drag on this projectile is negligible, the horizontal velocity
of this projectile would stay the same (at
) throughout the flight.
The vertical velocity
of this projectile would be
at the vertex (highest point) of its trajectory. (Otherwise, if
, this projectile would continue moving up and reach an even higher point. If
, the projectile would be moving downwards, meaning that its previous location was higher than the current one.)
Overall, the velocity of this projectile would be
when it is at the top of the trajectory. The kinetic energy
of this projectile (mass
) at the vertex of its trajectory would be:
.
Apply the Pythagorean Theorem to find the initial speed of this projectile:
.
Hence, the initial kinetic energy
of this projectile would be:
.
All that energy was from the work done in launching this projectile. Hence, the (useful) work done in launching this projectile would be
.
Out of the choices given, the best choice to explain the direction of the moving force of air is from area o high pressure to areas of low pressure. The correct answer is B.
:D HI YOUR ANSWER WOULD BE 8 NEWTONS TO DA RIGHT
22N to right + 14N to left