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Alenkinab [10]
3 years ago
9

Find the distance between the two points S (-5,-2) and T (-3,4).

Mathematics
1 answer:
icang [17]3 years ago
6 0

Answer:

d =2 \sqrt{10}

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

S (-5, -2)

T (-3, 4)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(-3+5)^2+(4+2)^2}
  2. Add:                              d = \sqrt{(2)^2+(6)^2}
  3. Evaluate:                      d = \sqrt{4+36}
  4. Add:                              d = \sqrt{40}
  5. Simplify:                       d =2 \sqrt{10}
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sergiy2304 [10]

Answer:

0.5996 is the probability that none contain high levels of contamination.

Step-by-step explanation:

We are given the following information:

We treat  lab specimen containing high levels of contamination as a success.

P( lab specimen containing high levels of contamination) = 0.12

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10. Given matrices A, B, and C below, perform the indicated operations if possible. If the operation is not possible, explain wh
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Answer(a):

Order of matrix A = 3x3 {because number of rows=3, number of columns=3}

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Order of matrix C = 1x3


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So 3A+B is possible.

We simply multiply all elements of A with 3 and add them with corresponding elements of B.

3\begin{bmatrix}2 &  -1& 0\\ 0 &  5& 0.3\\ 1 &  4&10 \end{bmatrix}+\begin{bmatrix}5 &  0& 2\\ 1 &  -3& 9\\ 2 &  0& 4\end{bmatrix}= \begin{bmatrix}11 &  -3& 2\\ 1 &  12& 9.9\\ 5 &  12& 34\end{bmatrix}


Answer(b):

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Answer(c):

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\begin{bmatrix}1 &3  &5 \end{bmatrix}*\begin{bmatrix}2 &  -1& 0\\ 0 &  5& 0.3\\ 1 &  4&10 \end{bmatrix}=\begin{bmatrix}1*2+3*0+5*1 & 1*-1+3*5+5*4 & 1*0+3*0.3+5*10\end{bmatrix}

= \begin{bmatrix}7 &  34& 50.9\end{bmatrix}

<em><u>If the matrix is not visible properly then look at the attached picture.</u></em>

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