Answer:
The claim that the current work teams can build room additions quicker than the time allotted for by the contract has strong statistical evidence.
Step-by-step explanation:
We have to test the hypothesis to prove the claim that the work team can build room additions quicker than the time allotted for by the contract.
The null hypothesis is that the real time used is equal to the contract time. The alternative hypothesis is that the real time is less thant the allotted for by the contract.

The significance level, as a storng evidence is needed, is α=0.01.
The estimated standard deviation is:

As the standard deviation is estimated, we use the t-statistic with (n-1)=15 degrees of freedom.
For a significance level of 0.01, right-tailed test, the critical value of t is t=2.603.
Then, we calculate the t-value for this sample:

As the t-statistic lies in the rejection region, the null hypothesis is rejected. The claim that the current work teams can build room additions quicker than the time allotted for by the contract has strong statistical evidence.
Answer:
we have
f(x)=x-6f(x)=x−6 -----> equation A
This is a linear equation with slope m=1m=1 and a y-intercept equal to -6−6
g(x)=x+6g(x)=x+6 -----> equation B
This is a linear equation with slope m=1m=1 and a y-intercept equal to 66
The function f(x) and g(x) are parallel lines
we know that
h(x)=f(x)+g(x)h(x)=f(x)+g(x)
Substitute
h(x)=x-6+x+6h(x)=x−6+x+6
h(x)=2xh(x)=2x
This is a linear equation with slope m=2m=2 that passes through the origin ( represent a direct variation)
Using a graphing tool
see the attached figure
Step-by-step explanation:
x²-10x+x-10
x(x-10)+1(x-10)
(x-10)(x+1)
x²+7x+10
x²+5x+2x+10
x(x+5)+2(x+5)
(x+5)(x+2).
hope this helps you.
for the first question it will be<u> </u><u>-</u><u>1</u><u>0</u><u> </u><u>.</u>
D. Line sw
Skew means they aren’t parallel, nor do they intersect.