Answer: the weight loss of zinc per hour is 6.1 g/h
Option c) 6.1 g/h is the correct answer.
Explanation:
Given that
copper cathode area is = 100 cm²
zinc anode area = 1 cm²
current density at the copper cathode = 0.05 A/cm²
The corrosion current can be converted to a rate of metal loss from its surface by using Faraday's law
W = ItM / nF
W is weight loss of metal
, I is current
,
I = iCu × ACu = 0.05 A/cm² x 100 cm² = 5.0 A
M is atomic weight of metal
Atomic mass of Zn = 65.38 g/mol
n = number of electron
F = Faraday’s constant = 96,500 C/mol
so we substitute
W loss of Zn = (5 A) × (3600/h) (65.38 g/mol) / [2 × (96,500 C/mol)
]
= 1176840 / 193000
= 6.098 ≈ 6.1 g/h
Therefore the weight loss of zinc per hour is 6.1 g/h
Option c) 6.1 g/h is the correct answer.
