Answer:
see explanation
Explanation:
Given quantities:
radius = r = 0.0558 [m]
current = I = 0.23 [A]

Now we solve this by obtaining the torque acting on the dipole

We obtain the magnetic moment vector M, first, |M| is defined as
, where A is the cross-section area of the loop which is
then
![|M| = 0.23*0.00978 = 0.00225 [A/m^2]](https://tex.z-dn.net/?f=%7CM%7C%20%3D%200.23%2A0.00978%20%3D%200.00225%20%5BA%2Fm%5E2%5D)
now the magnetic moment vector is equal to the magnetic dipole moment vector multiplied the magnitude we just obtained

Now:
a ) 
b) 
a) the determinant gives us:

b) the dot product gives = ![-1*-7.2*10^{-6} = 7.2*10^{-6}[J]](https://tex.z-dn.net/?f=%20-1%2A-7.2%2A10%5E%7B-6%7D%20%3D%207.2%2A10%5E%7B-6%7D%5BJ%5D)
Answer:
im pretty sure the answer is c please mark me brainliest
Answer:
Explanation:
The rms voltage = 140/√2 = 140/1.414 = 99 V.
Reactance of inductor = wL = 2 X 3.14 X 100 X 113 X 10⁻³ =70.96 ohm.
Total resistance in terms of vector = 50+70.96j
j is imaginary unit number
Magnitude of this resistance = √ 50² + 70.96² = 86.80 ohm
current in resistance (rms) ( I ) = 99/86.80 = 1.14 A.
Power dissipated in resistor = I² R = 1.14 X 1.14 X 50 = 65 W( approx)
Weight is based on density mass is not.