All categories

2 years ago

A pingpong ball has 2 kg m/s of momentum when thrown 8 m/s find the mass of the ball

Physics

1 answer:

avanturin [10]2 years ago

4 0

Answer:

0.25 kg

Explanation:

p = mv

2 = m(8)

2/8 = m(8)/8 *cancels

m = 1/4 OR 0.25 kg

You might be interested in

A temperature inversion happens when a _____ air layer traps pollution close to the surface of the earth.

LenaWriter [7]

When warm air layer traps pollution that is within the earth's surface, a temperature inversion usually takes place. In addition, at temperature inversion happens when the cold air overlays the warm air in the troposphere, which does not usually happen since warm air rises and cold air sinks by principle.

8 0

3 years ago

a car whose initial speed is 30 seconds m / s slows uniformly to a stop in 5.00 seconds what was the cars displacement

CaHeK987 [17]

Answer:

Explanation:

4 0

2 years ago

Which type of circuit is shown?

ivann1987 [24]

Answer:

I think it's D. open series circuit .

Explanation:

hope it helps you!

7 0

3 years ago

A ball on a string makes 25.0 revolutions in 9.37 s, in a circle radius 0.450 m. What is it’s velocity?

Sauron [17]

The velocity of the ball is 12.5 m/s

Explanation:

The velocity of the ball is given by the ratio between the distance covered by the ball and the time taken:

$v=\frac{d}{t}$

First, we calculate the distance covered. We know that the radius of the circle is

r = 0.450 m

And the length of the circumference is

$L=2\pi r = 2\pi(0.750)=4.7 m$

The ball makes 25.0 revolutions, so a total distance of

$d=(25.0)L=(25.0)(4.7)=117.5 m$

In a time of

t = 9.37 s

So, its velocity is

$v=\frac{117.5}{9.37}=12.5 m/s$

Learn more about velocity here:

brainly.com/question/5248528

#LearnwithBrainly

3 0

3 years ago

Read 2 more answers

If two charged objects in a laboratory are brought to a distance of 0.22 meters away from each other. What is

zysi [14]

Answer:

$q_2=2.47\times 10^{-4}\ C$

Explanation:

The charge on one object, $q_1=9.9\times 10^{-5}\ C$

The distance between the charges, r = 0.22 m

The force between the charges, F = 4,550 N

Let q₂ is the charge on the other sphere. The electrostatic force between two charges is given by the formula as follows :

$F=\dfrac{kq_1q_2}{r^2}\\\\q_2=\dfrac{Fr^2}{kq_1}\\\\q_2=\dfrac{4550\times (0.22) ^2}{9\times 10^9\times 9.9\times 10^{-5}}\\\\q_2=2.47\times 10^{-4}\ C$

So, the charge on the other sphere is $2.47\times 10^{-4}\ C$ .

7 0

3 years ago