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3 years ago

Help plz i have only tonight 11;59

Mathematics

1 answer:

Darina [25.2K]3 years ago

3 0

Answer:

Base = 16, height 64

Step-by-step explanation:

It's a triangle so u have to multiply it with 1/2 or divide by 2, x will equal both height and base:

(1/2)4x^2 = 512

Multiply 2 to both sides

4x^2 = 1024

divide both sides by 4

x^2 = 256

$\sqrt{x^2}$ = $\sqrt{256}$

x = 16, base is 16 and height is 16(4) = 64

Alright this took me some time but I got it now, u might think why 16 and 64? 16 times 64 is not 512, but the equation for a triangles area is $\frac{b h}{2}$ or b·h·1/2 , so if u plug the numbers into the equation it will equal 512:

16 · 64 · 1/2= 1024 · 1/2 = 512

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Step 2: Determine the index of the radical. The index tells you how many of a kind you need to put together to be able to move that number or variable from inside the radical to outside the radical. For example, if the index is 2 (a square root), then you need two of a kind to move from inside the radical to outside the radical. If the index is 3 (a cube root), then you need three of a kind to move from inside the radical to outside the radical.

Step 3: Move each group of numbers or variables from inside the radical to outside the radical. If there are nor enough numbers or variables to make a group of two, three, or whatever is needed, then leave those numbers or variables inside the radical. Notice that each group of numbers or variables gets written once when they move outside the radical because they are now one group.

Step 4: Simplify the expressions both inside and outside the radical by multiplying. Multiply all numbers and variables inside the radical together. Multiply all numbers and variables outside the radical together.

Shorter version:

Step 1: Find the prime factorization of the number inside the radical.

Step 2: Determine the index of the radical. In this case, the index is two because it is a square root, which means we need two of a kind.

Step 3: Move each group of numbers or variables from inside the radical to outside the radical. In this case, the pair of 2’s and 3’s moved outside the radical.

Step 4: Simplify the expressions both inside and outside the radical by multiplying.

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