At position of maximum height we know that the vertical component of its velocity will become zero
so the object will have only horizontal component of velocity
so at that instant the motion of object is along x direction
while if we check the acceleration of object then it is due to gravity
so the acceleration of object is vertically downwards
so it is along y axis
so here these two physical quantities are perpendicular to each other
so correct answer would be
<em>C)At the maximum height, the velocity and acceleration vectors are perpendicular to each other. </em>
Answer: The first one
Explanation: I think it's the first one because it says what is the "least" gravitational potential energy story between the prairie dog and Earth that said resting in its borrow is using less energy
Answer:
Acceleration = 9 × 10^5 m/s^2 ( deceleration )
Explanation:
From the first equation of motion:
V = u + at
15000 = 30000 + 60a
a = ( 15000-30000)/60
a = 9 × 10^5 m/s^2
A textbook would hit the ground first
Factors:
-Textbook weighs most
-Pillow is flat and fluffy not very aerodynamic) also is very light
-Paper airplane will glide to the ground do to its wings and will hit the ground last
Complete Question
The complete question is shown on the first uploaded image
Answer:
The components of reaction at the fixed support are
,
,
,
,
, ![M_z = 0 \ N\cdot m](https://tex.z-dn.net/?f=M_z%20%20%3D%200%20%5C%20%20N%5Ccdot%20m)
Explanation:
Looking at the diagram uploaded we see that there are two forces acting along the x-axis on the fixed support
These force are 400 N and
[ i.e the reactive force of 400 N ]
Hence the sum of forces along the x axis is mathematically represented as
![A_{(x)} - 400 = 0](https://tex.z-dn.net/?f=A_%7B%28x%29%7D%20%20-%20400%20%20%3D%200)
=> ![A_{(x)} = 400 \ N](https://tex.z-dn.net/?f=A_%7B%28x%29%7D%20%20%3D%20400%20%20%5C%20N)
Looking at the diagram uploaded we see that there are two forces acting along the y-axis on the fixed support
These force are 500 N and
[ i.e the force acting along the same direction with 500 N ]
Hence the sum of forces along the x axis is mathematically represented as
![A_{(y)} + 500 = 0](https://tex.z-dn.net/?f=A_%7B%28y%29%7D%20%20%2B%20500%20%20%3D%200)
=> ![A_{(y)} = -500 \ N](https://tex.z-dn.net/?f=A_%7B%28y%29%7D%20%20%3D%20-500%20%20%5C%20N)
Looking at the diagram uploaded we see that there are two forces acting along the z-axis on the fixed support
These force are 600 N and
[ i.e the reactive force of 600 N ]
Hence the sum of forces along the x axis is mathematically represented as
![A_{(z)} - 600 = 0](https://tex.z-dn.net/?f=A_%7B%28z%29%7D%20%20-%20600%20%20%3D%200)
=> ![A_{(z)} = 600 \ N](https://tex.z-dn.net/?f=A_%7B%28z%29%7D%20%20%3D%20600%20%20%5C%20N)
Generally taking moment about A along the x-axis we have that
![\sum M_x = M_x - 500 (0.75 + 0.5) + 600 ( 1 ) = 0](https://tex.z-dn.net/?f=%5Csum%20M_x%20%20%3D%20M_x%20%20-%20500%20%280.75%20%2B%200.5%29%20%2B%20600%20%28%201%20%29%20%3D%200)
=> ![M_x = 1225 \ N\cdot m](https://tex.z-dn.net/?f=M_x%20%20%3D%201225%20%5C%20%20N%5Ccdot%20m)
Generally taking moment about A along the y-axis we have that
![\sum M_y = M_y - 400 (0.75 ) + 600 ( 0.75 ) = 0](https://tex.z-dn.net/?f=%5Csum%20M_y%20%20%3D%20M_y%20%20-%20400%20%280.75%20%29%20%2B%20600%20%28%200.75%20%29%20%3D%200)
=> ![M_y = 750 \ N\cdot m](https://tex.z-dn.net/?f=M_y%20%20%3D%20750%20%5C%20%20N%5Ccdot%20m)
Generally taking moment about A along the z-axis we have that
![\sum M_z = M_z = 0](https://tex.z-dn.net/?f=%5Csum%20M_z%20%20%3D%20M_z%20%3D%200)
=> ![M_z = 0 \ N\cdot m](https://tex.z-dn.net/?f=M_z%20%20%3D%200%20%5C%20%20N%5Ccdot%20m)