1(km)cubed = (1,000 m) x (1,000 m) x (1,000 m) = 1 billion cubic meters
1.4 x 10 to the 9 cubic km = 1.4 x 10 to the 9 x (10 to the 9 cubic meters) =
1.4 x 10 to the 18 cubic meters.
Refer to the diagram shown below.
In this analysis, wind resistance is ignored, and g = 9.8 m/s².
The meat falls with zero vertical velocity, therefore the time, t, before the meat hits the ground is
![\frac{1}{2}*(9.8 \, \frac{m}{s^{2}})*(t \, s)^{2} = (15 \, m) \\ t= \sqrt{ \frac{15}{4.9} }= 1.75 \, s](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%2A%289.8%20%5C%2C%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%29%2A%28t%20%5C%2C%20s%29%5E%7B2%7D%20%3D%20%2815%20%5C%2C%20m%29%20%5C%5C%20t%3D%20%5Csqrt%7B%20%5Cfrac%7B15%7D%7B4.9%7D%20%7D%3D%201.75%20%5C%2C%20s)
If the fox catches the meat before it hits the ground, then the fox should travel a horizontal distance d in the same time that the meat travels a horizontal distance (7 -d).
The meat travels a distance of
7 - d = (1.2 m/s)*(1.75 s) = 2.1 m
or
d = 4.9 m
Let v = velocity of the fox when it catches the meat.
If the acceleration of the fox is a m/s², then
v = 1.75a
Also,
![d= \frac{1}{2} *(a \, \frac{m}{s^{2}} )*(1.75 \, s)^{2} = \frac{1}{2}( \frac{v}{1.75})^{2}*(1.75^{2}) \\ 4.9 = 0.875v^{2} \\ v^{2} = 5.6 \\ v = 2.366 \, m/s](https://tex.z-dn.net/?f=d%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%28a%20%5C%2C%20%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%29%2A%281.75%20%5C%2C%20s%29%5E%7B2%7D%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%28%20%5Cfrac%7Bv%7D%7B1.75%7D%29%5E%7B2%7D%2A%281.75%5E%7B2%7D%29%20%20%5C%5C%204.9%20%3D%200.875v%5E%7B2%7D%20%5C%5C%20v%5E%7B2%7D%20%3D%205.6%20%5C%5C%20v%20%3D%202.366%20%5C%2C%20m%2Fs)
Answer: 2.37 m/s (nearest hundredth)
We have that the speed of a body covering a distance of 320 km in 4h is mathematically given as
V=22.22m/s is
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Speed</h3>
From the question we are told
calculate the speed of a body covering a distance of 320 km in 4h
Generally the equation for the Speed is mathematically given as
![V=\frac{distance }{time}\\\\Therefore\\\\V=\frac{320*1000}{4*60*60}\\\\](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bdistance%20%7D%7Btime%7D%5C%5C%5C%5CTherefore%5C%5C%5C%5CV%3D%5Cfrac%7B320%2A1000%7D%7B4%2A60%2A60%7D%5C%5C%5C%5C)
V=22.22m/s
Hence
The speed of a body covering a distance of 320 km in 4h is
V=22.22m/s
For more information on Speed visit
brainly.com/question/7359669
What do you mean you need to be more specific