You compress a spring by a distance of 0.2 m. The spring has a spring constant of 37 N/m. When you release the spring, it snaps
2 answers:
At that point it is no longer trying to uncompress nor is it trying to stretch. This is the same thing as a pendulum at the bottom of its swing, no longer falling but not yet rising against gravity. Thus the kinetic energy there is the same as the potential energy when it is compressed. The energy of compression is
This gives E=0.5(37)(0.2)²=0.74J
This is the same as the kinetic energy when it is at natural length
This gives E=0.5(37)(0.2)²=0.74J
This is the same as the kinetic energy when it is at natural length
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Answer:
Explanation:
The instantaneous velocity of a point mass that executes a simple harmonic movement is given by:
Where:
Express the amplitude in meters:
The angular frequency can be found using the next equation:
Using the data provided:
At the equilibrium position:
The question is incomplete. The complete question is :
Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.
What is the frequency of the sound?
Solution :
Given :
The distance between the two loud speakers,
The speaker are in phase and so the path difference is zero constructive interference occurs.
At the point , the speakers are out of phase and so the path difference is
Therefore,
Thus the frequency is :
Hz
