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Yuki888 [10]
3 years ago
9

A 2.20 kg mass is at the origin. A

Physics
2 answers:
True [87]3 years ago
7 0

Answer:

0

Explanation:

Acellus Academy: No barriers! Enter your answer and you will get the green tick:)

Other schools: Try it!

Karolina [17]3 years ago
3 0

Answer:

0

Explanation:

F1 = G•2.2•4.66/3² (pointed right)

F2 = G•2.2•4.66/3² (pointed left)

subtract the two to get zero

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A Circular loop in the plane of a paper lies in a 0.65 TT magnetic field pointing into the paper. The loop's diameter changes fr
Kobotan [32]

Answer:

Explanation:

magnetic filed, B = 0.65 T

initial diameter, d = 17.5 cm

final diameter, d' = 6.6 cm

time, t = 0.48 s

(a) According to Lenz's law, the direction of induced current is clockwise.

(b) Let e is the induced emf.

initial area, A = π r² = 3.14 x 0.0875 x 0.0875 = 0.024 m²

final area, A' = π r'² = 3.14 x 0.033 x 0.033 = 0.00342 m²

change in area, ΔA = A - A' = 0.024 - 0.00342 = 0.02058 m²

The magnitude of induced emf is given by

e=\frac{d\phi }{dt}

e=B\frac{\Delta A }{dt}

e = 0.65 x 0.02058 / 0.48

e = 0.028 V

(c) R = 2.5 ohm

i = e / R

i = 0.028 / 2.5

i = 0.011 A

6 0
3 years ago
A moving object has a kinetic energy of 150J and a momentum of 20.3kgxm/s find the speed of the object in m/s
Irina-Kira [14]

Answer:

v = 14.78m/s

Explanation:

Given

KE = 150J

p = 20.3kgm/s

Required

Determine the object's speed

Kinetic Energy is calculated as:

KE = \frac{1}{2}mv^2

Make m the subject

m = \frac{2KE}{v^2}

Momentum is calculated as:

p = mv

Make m the subject

m = \frac{p}{v}

So, we have:

m = \frac{p}{v} and m = \frac{2KE}{v^2}

Equate both expressions: m = m

\frac{2KE}{v^2} = \frac{p}{v}

Multiply both sides by v

v *  \frac{2KE}{v^2} = \frac{p}{v}*v

\frac{2KE}{v} = p

Make v the subject

v = \frac{2KE}{p}

Substitute KE = 150J and p = 20.3kgm/s

v = \frac{2 * 150}{20.3}

v = \frac{300}{20.3}

v = 14.78m/s

5 0
3 years ago
If the density of a diamond is 3.5 g/cm", what would be the mass of a diamond whose
alexandr1967 [171]

Answer:

Explanation:

7 0
4 years ago
A billiard ball moves with 3 kg⋅m/s of momentum and strikes three other billiard balls. What is the total momentum of the balls
maxonik [38]

A billiard ball moves with 3 kg⋅m/s of momentum and strikes three other billiard balls that have been just sitting there at rest and not moving.

The total momentum of all four balls after the collision is <em>3 kg⋅m/s</em>, because momentum is not created or destroyed.  The total amount of it after an event is the same as the total amount of it before the event.

3 0
3 years ago
Don’t need to answer a question just say something and you’ll get Marked brainliest (Free points WONT GET BRAINLIEST RIGHT AWAY)
stiks02 [169]

Answer:

a

Explanation:

7 0
3 years ago
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