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White raven [17]
3 years ago
8

Suppose Galileo dropped a lead ball (100 kilograms) and a glass ball (1 kilogram) from the Leaning Tower of Pisa. Which one hit

the ground first?
Physics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

They will both hit the ground at the same time

Explanation:

You might be interested in
Geologists apply various methods to study the layers of the Earth. Which of the following is NOT a method used to study the Eart
77julia77 [94]

Answer:

A. Scientists use seismic computer models to measure the atmospheric conditions above the Earth's crust

Explanation:

why would use atmosphere to study the layers of earth? dont think thats possible

8 0
3 years ago
A helicopter goes straight up 500m from a landing pad. It then goes north 20m. Then it goes down 452m. a) What is the displaceme
gavmur [86]

Answer:

a

  x-component             20 \  m

y-component     500 -  452 =  48 \  m

b

 Magnitude d  =  52 \  m

direction is  \theta  = 67.4^o

Explanation:

From the question we are told that

   The first  vertical distance is  y_1   = 500 \  m

    The  first horizontal distance  is  x =  20 \  m

    The  second vertical distance is  y_2  =  452 \  m

Generally the displacement is  

x-component             20 \  m

y-component     500 -  452 =  48 \  m

Generally the helicopters displacement is mathematically evaluated as  

       d  =  \sqrt{ x- component ^2  +  y- component ^2 }

      d  =  \sqrt{ 20t ^2  + 48 ^2 }

      d  =  52 \  m

The  direction is the angle the displacement of the helicopter makes with the horizontal which is mathematically evaluated as

         \theta  = tan ^{-1}[ \frac{48}{20}]

=>       \theta  = tan ^{-1}[ 2.4 ]

=>      \theta  = 67.4^o

   

3 0
3 years ago
An apple falls out of a tree from a height of 2.3m. what is the impact speed of the apple
Anuta_ua [19.1K]

Answer:6.71 m/s

Explanation:

Given

Apple fall from a height of h=2.3 m  

We need to find the impact speed of apple which can be given by using

v^2-u^2=2gh  

where v=final velocity

u=initial velocity

h=Displacement

Assuming initial velocity to be zero

substituting the value we get

v^2-0=2\times 9.8\times 2.3  

v=\sqrt{2\times 9.8\times 2.3}  

v=6.71\ m/s  

5 0
3 years ago
An air bubble at the bottom of a lake 36.0 m deep has a volume of 1.22 cm^3. If the temperature at the bottom is 5.9°C and at th
AlexFokin [52]

Answer:

volume of the bubble just before it reaches the surface is 5.71 cm³

Explanation:

given data

depth h = 36 m

volume v2 = 1.22 cm³ = 1.22 × 10^{-6} m³

temperature bottom t2 = 5.9°C = 278.9 K

temperature top  t1 = 16.0°C = 289 K

to find out

what is the volume of the bubble just before it reaches the surface

solution

we know at top atmospheric pressure is about P1 = 10^{5} Pa

so pressure at bottom P2 = pressure at top + ρ×g×h

here ρ is density and h is height and g is 9.8 m/s²

so

pressure at bottom P2 = 10^{5} + 1000 × 9.8 ×36

pressure at bottom P2 =4.52 × 10^{5}  Pa

so from gas law

\frac{P1*V1}{t1} = \frac{P2*V2}{t2}

here p is pressure and v is volume and t is temperature

so put here value and find v1

\frac{10^{5}*V1}{289} = \frac{4.52*10^{5}*1.22}{278.9}

V1 = 5.71 cm³

volume of the bubble just before it reaches the surface is 5.71 cm³

6 0
3 years ago
Part A
cupoosta [38]

Answer:

A) U₀ = ϵ₀AV²/2d

B) U₁ = (ϵ₀AV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

C) U₂ = (kϵ₀AV²)/2d

Explanation:

A) The energy stored in a capacitor is given by (1/2) (CV²)

Energy in the capacitor initially

U₀ = CV²/2

V = voltage across the plates of the capacitor

C = capacitance of the capacitor

But the capacitance of a capacitor depends on the geometry of the capacitor is given by

C = ϵA/d

ϵ = Absolute permissivity of the dielectric material

ϵ = kϵ₀

where k = dielectric constant

ϵ₀ = permissivity of free space/air/vacuum

A = Cross sectional Area of the capacitor

d = separation between the capacitor

If air/vacuum/free space are the dielectric constants,

So, k = 1 and ϵ = ϵ₀

U₀ = CV²/2

Substituting for C

U₀ = ϵ₀AV²/2d

B) Now, for U₁, the new distance between plates, d₁ = 3d

U₁ = ϵ₀AV²/2d₁

U₁ = ϵ₀AV²/(2(3d))

U₁ = (ϵ₀AV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

C) U₂ = CV²/2

Substituting for C

U₂ = ϵAV²/2d

The dielectric material has a dielectric constant of k

ϵ = kϵ₀

U₂ = (kϵ₀AV²)/2d

3 0
4 years ago
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