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igor_vitrenko [27]
3 years ago
9

Please help i give brainliest​

Engineering
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

A mock-up

Explanation:

It is made of cheap and easy to access parts.

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Go to the sd_messier.html file. Within the document head, create links to the sd_base.css, sd_layout.css, and sd_effects.css sty
makkiz [27]

Answer:

Explanation:

1. Inside tss_coach.html <head> section, include these two lines of code:

<link rel="stylesheet" href="coach_layout.css">

<link rel="stylesheet" href="coach_styles.css">

These two lines links the CSS files with the HTML code.

2. Include the below two lines at the top of the file coach_styles.css and before the comment section

@charset "UTF-8"

@font-face { font-family: Nobile;

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6 0
3 years ago
What are the ropes of secretaries and treasures in a meeting​
Nastasia [14]

Answer:

To prepare and issue notices and agendas of all meetings in consultation with the chairman, and to ensure that any background papers are available well before the meeting. To attend and take the minutes of every committee meeting. To circulate minutes to all committee members, and to conduct the correspondence

Explanation:

I think you want to say roles.

4 0
3 years ago
X²-12x=0 ПЖ срочно реально решите помагие ​
nika2105 [10]

Answer:

формула pq sry i dont speak russian lol but thats the solution of the equation

4 0
3 years ago
A motor whose pulley is 80mm in diameter is rotating at 30 revolutions per minute and is connected by a belt to another pulley o
Firdavs [7]

Answer:

169

Explanation:

ye men thats the answer

8 0
3 years ago
A steam power plant receives heat from a furnace at a rate of 300 GJ/h. Heat losses to the surrounding air from the steam as it
shutvik [7]

Answer:

Net Power output  144 GJ/h

\eta = 51.41 %

Explanation:

Given data:

Heat received = 300 GJ/h

                        = \frac{300\times 10^9}{3600} J/s

                        = 77.78 \times 10^6 W

Heat lost Q_2 = 16 GJ/h

Heat to the water = Q_3 = 140 GJ/h

Net Power output = Q_1 - Q_2 -Q_3

                  = 300 - 16 - 140

                   = 144 GJ/h

                   =\frac{144\times 10^9}{3600} = 40\times 10^8 J/s

thermal efficiency

\eta = \frac{net\ power}{heat\ supplied}

= \frac{40\times 10^6}{ 77.78 \times 10^6}

       = 0.514 = 51.41 %

7 0
3 years ago
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