The solution would be like
this for this specific problem:
<span>1.0
</span>atm + 2.0 atm
+ 3.0 atm = 6.0 atm
So the partial pressure of
the helium 3.0 atm.
<span>I hope this helps and if you
have any further questions, please don’t hesitate to ask again.</span>
The volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.
We will use the ideal gas equation-
<u>PV=nRT</u>
P=Pressure
V=volume
n=no. of moles
T=temperature
In this question temperature and pressure will remains constant then the above equation can be rewritten as-
where V1= initial volume of the balloon
V2= volume of the balloon when the mass of oxygen gas is decreased to 50g
now, substitute the values in the above equation-
100/3.12=V2/1.56
hence, the volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.
learn more about the ideal gas equation here:
brainly.com/question/1056445
#SPJ10
Okay so this is in order of the blanks
matter
potential
kinetic
physical
food.
Answer:
64,433.6 Joules
Explanation:
<u>We are given</u>;
- Volume of water as 220 mL
- Initial temperature as 30°C
- Final temperature as 100°C
- Specific heat capacity of water as 4.184 J/g°C
We are required to calculate the amount of heat required to raise the temperature.
- We know that amount of heat is calculated by;
Q = mcΔT , where m is the mass, c is the specific heat, ΔT is the change in temperature.
Density of water is 1 g/mL
Thus, mass of water is 220 g
ΔT = 100°C - 30°C
= 70°C
Therefore;
Amount of heat, Q = 220g × 4.184 J/g°C × 70°C
= 64,433.6 Joules
Thus, the amount of heat required to raise the temperature of water is 64,433.6 Joules
