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yanalaym [24]
3 years ago
12

Please answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!! URGENT

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

SSS means Side-Side-Side.

The reason JKM and LKM are congruent is because if you follow them each side will be equal to the other triangles angles if they're congruent

Step-by-step explanation:

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Select the correct answer.
Tpy6a [65]

Answer:

your answer is D.

Step-by-step explanation:

Using sine will give you 3*square root of 3

3 0
3 years ago
Read 2 more answers
Check all of the answers that are in the solution set of the inequality.
blsea [12.9K]
Well, plug in all the values.

(sqrt)3>3

False. 3 would be more than it's square root.

(sqrt)9>3
3>3

This is false. 3 is not bigger than 3. They are equal.

(sqrt)15>3 

3.8729..... >3

That is true,

(sqrt)10>3

3.1622>3 

This true.

-3 and 0 would not work either.

So, 

"C" and "D" are correct solutions.

I hope this helps!
~kaikers


7 0
4 years ago
Are the equations 3x=-9 and 4x=-12 equivilant? explain.
patriot [66]
Yes because if you simplify them, both are going to give x= -3
5 0
3 years ago
A handicap ramp that is 25 feet long coves a ground distance of 22 feet. To the nearest degree, what is the angle of elevation o
bazaltina [42]

Answer:

28.36°

Step-by-step explanation:

The problem represents a right angled triangle as shown in the diagram below.

The length of the handicap ramp is 25 feet.

The side ground distance covered by the ramp is the adjacent of the angle of the triangle and it is 22 feet.

To find the angle of elevation of the incline, we apply SOHCAHTOA:

cos θ = adj / hyp

Therefore:

cos \alpha = 22 / 25\\\\cos \alpha = 0.88\\\\\alpha = cos^{-1} 0.88\\\\\alpha = 28.36^o

The angle of elevation of the incline for the handicap ramp is 28.36°.

8 0
3 years ago
Is an estimate of 8 as the difference between 4.7 and -3.3 reasonable? Explain.
iris [78.8K]

\bf \underset{\textit{\large 3.3 + 4.7 = 8}}{\stackrel{\textit{3.3 units}}{\boxed{-3.3}\rule[0.35em]{10em}{0.25pt}}0\stackrel{\textit{4.7 units}}{\rule[0.35em]{17em}{0.25pt}\boxed{4.7}}}

3 0
3 years ago
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