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Explanation:
The given reaction at cathode will be as follows.
At cathode: ,
= -0.761 V
At anode: ,
= 0.761
Therefore, net reaction equation will be as follows.
Initial: 0.129 - - 0.427
Change: -0.047 - - -0.047
Equilibrium: (0.129 - 0.047) (0.427 - 0.047)
= 0.082 = 0.38
As for the given reaction is zero.
Hence, equation for calculating new cell potential will be as follows.
E_{cell} =
=
= 0.019
Thus, we can conclude that the cell potential of the given cell is 0.019.