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antoniya [11.8K]
4 years ago
15

Give the expression for the solubility product constant for baf2.

Chemistry
1 answer:
svetoff [14.1K]4 years ago
3 0

<span>Solubility product constant (Ksp) is </span>applied to the saturated ionic solutions<span> which are in equilibrium with its solid form. The solid is partially dissociated into its ions.</span><span>

For the BaF, the dissociation as follows;
BaF</span>₂(s) ⇄ Ba²⁺(aq) + 2F⁻(aq)

<span>
Hence,
        Ksp = [Ba</span>²⁺(aq)] [F⁻(aq)]²

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