Question

In an experiment you find the density of water to water to be 1.23 g.Ml.The theoritical value of the water's density is 1. 00 g/ml. Find the percent error

Answer 1

Answer:

The percent error is 23%

Explanation:

To find the percent error for the experiment carried out,

Percent error is given by the formula below

$PE = \frac{AE}{TV}$ ×$100$%

Where PE is the percent error

AE is the Absolute error

TV is the Theoretical value

Also, Absolute error (AE) can be determined from

Absolute error (AE)  = /Theoretical value(TV) - Experimental value (EV)/

Now, from the question,

Experimental value (EV) = 1.23 g/mL

Theoretical value (TV) = 1.00 g/mL

From,

Absolute error (AE)  = /Theoretical value(TV) - Experimental value (EV)/

Absolute error (AE) = /1.00 g/mL - 1.23 g/mL/

Absolute error (AE) = / - 0.23 g/mL/

Absolute error (AE) = 0.23 g/mL

This is the Absolute error

Now, for the Percent error

$PE = \frac{AE}{TV}$ ×$100$%

$PE = \frac{0.23}{1.00}$ ×$100$%

$PE = 23$ %

Hence, the percent error (PE) is 23%