Answer:
1.005 cm³
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 0.650 cm³
V₂ = ?
P₁ = 1.54 atm
P₂ = 1.01 atm
T₁ = 12°C
T₂ = 16 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (12 + 273.15) K = 285.15 K
T₂ = (16 + 273.15) K = 289.15 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 1.005 cm³</u>
Answer may be 1 co2 I might be wrong sorry
Answer:
See explanation
Explanation:
The word equation is just a statement of the reaction in words as follows;
Magnesium oxide ----> Magnesium metal + oxygen gas
An unbalanced stoichiometric equation doesn't have equal number of atoms of each element on both sides.
Hence the unbalanced stoichiometric equation is as follows;
MgO(s) -----> Mg(s) + O2(g)
You must use 2.50 mL of the concentrated solution to make 10.0 mL of the dilute solution.
We can use the dilution formula
<em>V</em>_1<em>C</em>_1 = <em>V</em>_2<em>C</em>_2
where
<em>V</em> represents the volumes and
<em>C</em> represents the concentrations
We can rearrange the formula to get
<em>V</em>_2 = <em>V</em>_1 × (<em>C</em>_1/<em>C</em>_2)
<em>V</em>_1 = 10.0 mL; <em>C</em>_1 = 5.00 g/100. mL
<em>V</em>_2 = ?; ____<em>C</em>_2 = 20.0 g/100. mL
∴ <em>V</em>_2 = 10.0 mL × [(5.00 g/100. mL)/(20.0 g/100. mL)] = 10.0 mL × 0.250
= 2.50 mL
In order to solve this type of problem, we take a look at the subscript of each element involved in the compound. These values signifies the number of particles present of that element in that compound. The calculation is as follows:
2.4 moles P2O10 ( 2 moles P / 1 moles P2O10 ) = 4.8 moles P
