Food consumption affects the rate of alcohol absorption in the bloodstream.
Explanation:
The type of food and therefore the amount<span> of food that </span>is a gift<span> in your </span>epithelial duct once you<span> consume alcohol have </span>the foremost<span> direct </span>impact<span> on </span>the speed<span> of alcohol absorption.</span>
<span>When you consume alcohol on </span>the associate<span> empty </span>abdomen<span>, the alcohol </span>is sometimes<span> absorbed </span>within the<span> blood </span>among<span> fifteen minutes to two-and-a-half hours. If </span>you have got<span> a moderate </span>quantity<span> of food in your </span>abdomen once you<span> drink, that speed slows </span>all the way down to<span> thirty minutes </span>to a few<span> hours. If you’re drinking on a full </span>abdomen<span>, alcohol absorption ranges from </span>3 to 6<span> hours.</span>
Answer:
The choice of the answer is fourth option that is -61 degrees.
Therefore the temperature drop is -61°Centigrade.
Explanation:
Given:
The temperature in a town started out at 55 degrees
Start temperature = 55°Centigrade. (Initial temperature)
End of the Day = -6°Centigrade. (Final temperature)
To Find:
How far did the temperature drop?
Solution:
We will have,
Substituting the above values in it we get
Therefore the temperature drop is -61°Centigrade.
Answer: At temperature of 269 K the gas would occupy 1.33 L at 217 kPa
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 147 kPa
= final pressure of gas = 217 kPa
= initial volume of gas = 1.8 L
= final volume of gas = 1.33 L
= initial temperature of gas = 
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
Thus at 269 K temperature the gas would occupy 1.33 L at 217 kPa
The 2 L of sucrose stock solution would contain similar
concentration with the 100 mL aliquot. Therefore the concentration of aliquot
is still 2 M.
The molar mass of sucrose is 342.3 g / mol. Therefore the
mass in a 100 mL (0.1 L) aliquot is:
mass = (2 mol / L) * 0.1 L * (342.3 g / mol)
<span>mass = 68.46 g</span>
