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mars1129 [50]
3 years ago
9

Mass Number

Physics
1 answer:
larisa [96]3 years ago
3 0

Answer:

3

Explanation:

mass number minus the atomic number

35-32

3

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A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s . Estimate the net force on the person if he or sh
zalisa [80]

Complete question:

Seat belts and air bags save lives by reducing the forces exerted on the driver and passengers in an automobile collision. Cars are designed with a "crumple zone" in the front of the car. In the event of an impact, the passenger compartment decelerates over a distance of about 1 m as the front of the car crumples. An occupant restrained by seat belts and air bags decelerates with the car. In contrast,  a passenger not wearing a seat belt or using an air bag decelerates over a distance of 5mm.

(a) A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s . Estimate the net force on the person if he or she is wearing a seat belt and if the air bag deploys.

Answer:

The net force on the person as the air bad deploys is -6750 N backwards

Explanation:

Given;

mass of the passenger, m = 60 kg

velocity of the car at impact, u = 15 m/s

final velocity of the car after impact, v = 0

distance moved as the front of the car crumples, s = 1 m

First, calculate the acceleration of the car at impact;

v² = u² + 2as

0² = 15² + (2 x 1)a

0 = 225 + 2a

2a = -225

a = -225 / 2

a = -112.5 m/s²

The net force on the person;

F = ma

F = 60 (-112.5)

F = -6750 N backwards

Therefore, the net force on the person as the air bad deploys is -6750 N backwards

4 0
3 years ago
1.) What is the equation for Average Speed?
jok3333 [9.3K]

Answer:

Speed = Distance / Time

Explanation:

here you go :)

4 0
3 years ago
Read 2 more answers
An AC adapter for a telephone-answering unit uses a transformer to reduce the line voltage of 120 V (rms) to a voltage of 9.0 V.
Illusion [34]

Answer:

1. The number of turns on the secondary output is 18

2. The root mean square power delivered to the transformer is 48 Watts.

Explanation:

A transformer is an electronic device that can be used for increasing or decreasing the value of a given voltage. It consists of primary coils and secondary coil of a definte number of turns. When voltage flows in the primary coil, it induces voltage in the secondary coil. The two types are: step-up and step down transformers.

1. For a given transformer,

          \frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }

where V_{s} is the value of the induced voltage in the secondary coil, V_{p} is he voltage in the primary coil, and N_{s} is the number of turns of the secondary coil, N_{p} is the number of turns in the primary coil.

From the question,

V_{s}  = 9.0 V, V_{p} = 120 V, N_{p} = 240, N_{s} = ?

So that,

           N_{s} = \frac{V_{s}*N_{p}  }{V_{p} }

                = \frac{9 * 240}{120}

               = 18

The number of turns on the secondary output is 18.

2. Power_{rms} = I_{rms} × V_{rms}

                    = 0.4 × 120

                   = 48 W

The rms power delivered to the transformer is 48 Watts.

8 0
3 years ago
How many moons does Venus have?<br> a. 3<br> b. 6<br> c. 0<br> d. 12
baherus [9]
<span>The question is asking how many moons Venus, the planet, has and the answer is 0 -Venus doesn't have any moons. Another planet that doesn't have any moons is Mercury. Earth has one moon and Mars has two moons. Jupiter has 4 moons and the most impressive is Saturn, with its 53 confirmed moons (as claimed by Nasa)!</span>
3 0
4 years ago
Read 2 more answers
At a particular instant the magnitude of the momentum of a planet is 2.60 × 10^29 kg·m/s, and the force exerted on it by the sta
aleksley [76]

Answer:

F=(-4.8*10^22,0,0) N

Explanation:

<u>Given  :</u>

We are given the magnitude of the momentum of the planet and let us call this momentum (p_now) and it is given by p_now = 2.60 × 10^29 kg·m/s. Also, we are given the force exerted on the planet F = 8.5 × 10^22 N. and the angle between the planet and the star is Ф = 138°

Solution :

We are asked to find the parallel component of the force F The momentum here is not constant, where the planet moving along a curving path with varying speed where the rate change in momentum and the force may be varying in magnitude and direction. We divide the force here into two parts: a parallel force F to the momentum and a perpendicular force F' to the momentum.  

The parallel force exerted to the momentum will speed or reduce the velocity of the planet and does not change its moving line. Let us apply the direction cosines, we could obtain the parallel force as next  

F=|F|cosФp            (1)

Where the parallel force F is in the opposite direction of p as the angle between them is larger than 90°. Now we can plug our values for 0 and I F I into equation (1) to get the parallel force to the planet  

F=|F|cosФp

 =-4.8*10^22 N*p

<em>As this force is in one direction, we could get its vector as next  </em>

F=(-4.8*10^22,0,0) N

F=(0,-4.8*10^22,0) N

F=(0,0-4.8*10^22) N

The cosine of 138°, the angle between F and p is, is a negative number, so F is opposite to p. The magnitude of the planet's momentum will decrease.

8 0
3 years ago
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