Answer:
y^2 +7y-30
Step-by-step explanation:
Step 1: Use FOIL
y·y = y^2
y· 10= 10y
-3·y= -3y
-3·10= -30
Step 2: <em>combine like terms</em>
y^2+ 10y-3y-30
7^2+ 7y-30
and thats all :)
hope this helped
Answer:
Use pythagorean theorem.
Step-by-step explanation:
The length of the shorter sides are 1 & 4
1^2+4^2=c^2
1+16=c^2
17=c^2
So, the length, rounded to the nearest whole inch, would be 4.
To find the perimeter, you need to find the side lengths first.
The short sides are 6 & 7.
6^2+7^2=c^2
36+49=c^2
85=c^2
So the length for that would be 8, in the nearest whole number.
Add all of the side lengths together.
6+7+8= 21
The perimeter is 21.
You can turn 5 into 10/2 and add to x/2
then you need to use simple algebra to left the x alone in the equation so you need to multiply both sides by 2 so you get
2y=10+x
then you need to subtract both sides a 10 so
2y-10=x
now change the x to f'(x) and y to x so:
f'(x)=2x-10
Answer:
26
Step-by-step explanation:
10+(10x3)-2(10-3)=
10+30+-2(7)=
40-14=
26
The answer is 3 because 3×5=15
