Ask question

Ask question

All categories

3 years ago

10

A manufacturer has been asked to produce 100 customized metal discs with a particular pattern engraved on them. Which production

process should be selected?

2 answers:

topjm [15]3 years ago

8 0

I’m just here for points because I have test and I need them lol

saul85 [17]3 years ago

3 0

Answer:

Job Shop production

Explanation:

You might be interested in

Advocard [28]

Answer:

I would say C

Explanation:

let me know if im right

3 0

2 years ago

Read 2 more answers

Convert 850 nm wavelength into frequency, eV, wavenumber, joules and ergs.

Sholpan [36]

Answer:

Frequency = $3.5294\times 10^{14}s^{-1}$

Wavenumber = $1.1765\times 10^6m^{-1}$

Energy = $2.3365\times 10^{-19}J$

Energy = 1.4579 eV

Energy = $2.3365\times 10^{-12}erg$

Explanation:

As we are given the wavelength = 850 nm

conversion used : $(1nm=10^{-9}m)$

So, wavelength is $850\times 10^{-9}m$

The relation between frequency and wavelength is shown below as:

$Frequency=\frac{c}{Wavelength}$

Where, c is the speed of light having value = $3\times 10^8m/s$

So, Frequency is:

$Frequency=\frac{3\times 10^8m/s}{850\times 10^{-9}m}$

$Frequency=3.5294\times 10^{14}s^{-1}$

Wavenumber is the reciprocal of wavelength.

So,

$Wavenumber=\frac{1}{Wavelength}=\frac{1}{850\times 10^{-9}m}$

$Wavenumber=1.1765\times 10^6m^{-1}$

Also,

$Energy=h\times frequency$

where, h is Plank's constant having value as $6.62\times 10^{-34}J.s$

So,

$Energy=(6.62\times 10^{-34}J.s)\times (3.5294\times 10^{14}s^{-1})$

$Energy=2.3365\times 10^{-19}J$

Also,

$1J=6.24\times 10^{18}eV$

So,

$Energy=(2.3365\times 10^{-19})\times (6.24\times 10^{18}eV)$

$Energy=1.4579eV$

Also,

$1J=10^7erg$

So,

$Energy=(2.3365\times 10^{-19})\times 10^7erg$

$Energy=2.3365\times 10^{-12}erg$

5 0

3 years ago

Calculate the biaxial stresses σ1 and σ2 for the biaxial stress case, where ε1 = .0020 and ε2 = –.0010 are determined experiment

Llana [10]

Answer:

i) σ1 = 133.5 MPa

σ2 = -2427 MPa

ii) 78.89 MPa

Explanation:

Given data:

ε1 = 0.0020 and ε2 = –0.0010

E = 71 GPa

v = 0.35

<u>i) Determine the biaxial stresses σ1 and σ2 using the relations below</u>

ε1 = σ1 / E - v (σ2 / E) -----( 1 )

ε2 = σ2 / E - v (σ1 / E) -------( 2 )

resolving equations 1 and 2

σ1 = E / 1 - v^2 { ε1 + vε2 } ---- ( 3 )

σ2 = E / 1 - v^2 { ε2 + vε1 } ----- ( 4 )

input the given data into equation 3 and equation 4

σ1 = 133.5 MPa

σ2 = -2427 MPa

<u>ii) Calculate the value of the maximum shear stress ( Zmax )</u>

Zmax = ( σ1 - σ2 ) / 2

= 133.5 - ( - 2427 ) / 2

= 78.89 MPa

3 0

3 years ago

Consider an adiabatic throttling valve with water entering at pressure of 1.5 MPa, a temperature of 150°C and a velocity of 4.5

Marta_Voda [28]

Answer:

So the exit velocity of water is 4.5 m/s

Explanation:

Given that

Water entering pressure = 1.5 MPa

Temperature = 150°C

Velocity = 4.5 m/s

From first law of thermodynamics for open system

$h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+W$

Here given that valve is adiabatic so Q= 0

In valve W= 0

Wen also also know that throttling process is an constant enthaply process so

$h_1=h_2$

$h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+W$

$h_1+\dfrac{V_1^2}{2}+0=h_1+\dfrac{V_2^2}{2}+0$

So from above equation we can say that

$V_2=V_1$

So the exit velocity of water is 4.5 m/s

5 0

3 years ago

What do safegaurding devices do to protect the worker

Elenna [48]

Answer:

Prevent contact: The safeguard must prevent hands, arms, and any other part of a worker's body from making contact with dangerous moving parts. A good safeguarding system eliminates the possibility of the operator or another worker placing parts of their bodies near hazardous moving parts.

6 0

3 years ago