Answer:
<em>a) 4.51 lbf-s^2/ft</em>
<em>b) 65.8 kg</em>
<em>c) 645 N</em>
<em>d) 23.8 lb</em>
<em>e) 65.8 kg</em>
<em></em>
Explanation:
Weight of the man on Earth = 145 lb
a) Mass in slug is...
32.174 pound = 1 slug
145 pound =
slug
= 145/32.174 = <em>4.51 lbf-s^2/ft</em>
b) Mass in kg is...
2.205 pounds = 1 kg
145 pounds =
kg
= 145/2.205 = <em>65.8 kg</em>
c) Weight in Newton = mg
where
m is mass in kg
g is acceleration due to gravity on Earth = 9.81 m/s^2
Weight in Newton = 65.8 x 9.81 = <em>645 N</em>
d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,
1 m/s^2 = 3.2808 ft/s^2
m/s^2 = 5.30 ft/s^2
= 5.30/3.2808 = 1.6155 m/s^2
weight in Newton = mg = 65.8 x 1.6155 = 106
weight in pounds = 106/4.448 = <em>23.8 lb</em>
e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth
mass on the moon = <em>65.8 kg</em>
Answer:
%Program prompts user to input vector
v = input('Enter the input vector: ');
%Program shows the value that user entered
fprintf('The input vector:\n ')
disp(v)
%Loop for checking all array elements
for i = 1 : length(v)
%check if the element is a positive number
if v(i) > 0
%double the element
v(i) = v(i) * 2;
%else the element is negative number.
else
%triple the element
v(i) = v(i) * 3;
end
end
%display the modified vector
fprintf('The modified vector:\n ')
disp(v)
Answer:

Explanation:
Given data:
flow rate = 10 gallon per minute = 0.0223 ft^3/sec
diameter = 0.75 inch
we know discharge is given as
Q = VA
solve for velocity V = \frac{Q}{A}[/tex]

V = 7.27 ft/sec
we know that Reynold number



calculate the
ratio to determine the fanning friction f

from moody diagram f value corresonding to Re and
is 0.037
for horizontal pipe


where 1.94 slug/ft^3is density of water

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