Answer:
What is the difference Plastic vs elastic deformation
Explanation:
The elastic deformation occurs when a low stress is apply over a metal or metal structure, in this process, the stress' deformation is temporary and it's recover after the stress is removed. In other words, this DOES NOT affects the atoms separation.
The plastic deformation occurs when the stress apply over the metal or metal structure is sufficient to deform the atomic structure making the atoms split, this is a crystal separation on a limited amount of atoms' bonds.
Answer:
A) About
newtons
B) 76.518 newtons
C) 111.834 newtons
Explanation:
A)
, where G is the universal gravitational constant, M 1 and 2 are the masses of both objects in kilograms, and r is the radius in meters. Plugging in the given numbers, you get:
![F_g=\dfrac{(6.67408 \times 10^{-11})(7.8)(11.4)}{(0.8)^2}\approx 9.273 \times 10^{-9}](https://tex.z-dn.net/?f=F_g%3D%5Cdfrac%7B%286.67408%20%5Ctimes%2010%5E%7B-11%7D%29%287.8%29%2811.4%29%7D%7B%280.8%29%5E2%7D%5Capprox%209.273%20%5Ctimes%2010%5E%7B-9%7D)
B) You can find the weight of each object on Earth because you know the approximate acceleration due to gravity is 9.81m/s^2. Multiplying this by the mass of each object, you get a weight for the first particle of 76.518 newtons.
C) You can do a similar thing to the previous particle and find that its weight is 11.4*9.81=111.834 newtons.
Hope this helps!
Answer:Prepare plans with detailed drawings that include project specifications and cost estimates.
Design and execute engineering experiments to create workable solutions.
Develop engineering calculations, diagrams and technical reports.
Explanation:
Answer:
Net discharge per hour will be 3.5325 ![m^3/hr](https://tex.z-dn.net/?f=m%5E3%2Fhr)
Explanation:
We have given internal diameter d = 25 mm
Time = 1 hour = 3600 sec
So radius ![r=\frac{d}{2}=\frac{25}{2}=12.5mm=12.5\times 10^{-3}m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%7D%7B2%7D%3D%5Cfrac%7B25%7D%7B2%7D%3D12.5mm%3D12.5%5Ctimes%2010%5E%7B-3%7Dm)
We know that area is given by
![A=\pi r^2=3.14\times (12.5\times 10^{-3})^2=490.625\times 10^{-6}m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%3D3.14%5Ctimes%20%2812.5%5Ctimes%2010%5E%7B-3%7D%29%5E2%3D490.625%5Ctimes%2010%5E%7B-6%7Dm%5E2)
We know that discharge is given by
, here A is area and V is velocity
So ![Q=AV=490.625\times 10^{-6}\times 2=981.25\times 10^{-6}m^3/sec](https://tex.z-dn.net/?f=Q%3DAV%3D490.625%5Ctimes%2010%5E%7B-6%7D%5Ctimes%202%3D981.25%5Ctimes%2010%5E%7B-6%7Dm%5E3%2Fsec)
So net discharge in 1 hour = ![981.25\times 10^{-6}m^3/sec\times 3600=3.5325m^3/hour](https://tex.z-dn.net/?f=981.25%5Ctimes%2010%5E%7B-6%7Dm%5E3%2Fsec%5Ctimes%203600%3D3.5325m%5E3%2Fhour)