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Naya [18.7K]
3 years ago
9

Trees grow in bulk in outward direction​

Engineering
1 answer:
Aloiza [94]3 years ago
4 0
Yes they do grow in outward direction
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In highways the far left lane is usually the _____
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Why is it important to keep hand tools free of oil and grease?
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keeps it from rusting

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How do you use the brakes in an airplane?
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3 years ago
Kerosene flows through 3/4 standard type K drawn copper tube. The pressure drop measured at two points 50 m apart is 130 kPa. De
Anettt [7]

Answer:

Q=4.98\times 10^{-3}\ m^3/s

Explanation:

Given that

L= 50 m

Pressure drop = 130 KPa

For Copper tube is 3/4 standard type K drawn tube

Outside diameter=22.22 mm

Inside diameter=18.92 mm

Dynamic viscosity for kerosene

\mu =0.00164\ Pa.s

Pressure difference given as

\Delta P=\dfrac{128\mu QL}{\pi d_i^4}

Where

L is length of tube

μ is dynamic viscosity

Q is volume flow rate

d is inner diameter of tube

ΔP is pressure drop

Now by putting the values

\Delta P=\dfrac{128\mu QL}{\pi d_i^4}

130\times 1000=\dfrac{128\times 0.00164\times 50\times Q}{\pi\times 0.0189^4}

Q=4.98\times 10^{-3}\ m^3/s

So flow rate is Q=4.98\times 10^{-3}\ m^3/s

7 0
3 years ago
Calculate the ratio of change in the mass of the molecules of a gas to the initial mass, if its
kirill115 [55]

<h2>Answer:</h2>

<h3>Required Answer is as follows :-</h3>

  • \sf \dfrac{P _{i}}{ P_{f}} = \dfrac{3}{4}

  • 3/4 = (⅓ × m₁/Volume × V²)/(⅓ × m₂/Volume) × (V/2)²

  • ¾ = m₁/Volume × (V)²/m₂/Volume × (V/2)²

  • ¾ = m₁ × (V)²/m₂ × (V²/4)

  • ¾ = m₁/m₂ × 4

  • m₂ = 4 × 4/3 = 16/3m₁

\bold{   } 

<h3>Now,</h3>
  • ∆m = m₂ - m₁
  • ∆m = 16m₂/3 - m₁ = 13m₁/3
  • Ratio = (13m₁/3)/ m₁
  • Ratio = 13/3

Ratio = 13:3

\bold{   } 

<h3>Know More :-</h3>

Mass => It is used to measure it's resistance to its acceleration. SI unit of mass is Kg.\bold{   } 

3 0
3 years ago
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