3 years ago

Gshyevdnmdcicm gngjc

Engineering

1 answer:

Len [333]3 years ago

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(a) A 10.0-mm-diameter Brinell hardness indenter produced an indentation 2.3 mm in diameter in a steel alloy when a load of 1000

vampirchik [111]

Answer:

(a) We are asked to compute the Brinell hardness for the given indentation. for HB, where P= 1000 kg, d= 2.3 mm, and D= 10 mm.

Thus, the Brinell hardness is computed as

$HB=2P/\pi D{D-\sqrt{D^2-d^2}$

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(b) This part of the problem calls for us to determine the indentation diameter d which will yield a 270 HB when P= 500 kg.

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option 2 is your answer... thanks .. hope it helps

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