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3 years ago

Explain the use of the Kanban system in a production line?

Engineering

1 answer:

AURORKA [14]3 years ago

7 0

Answer:

Kanban is a tool which are design to reduce the insignificant time in the production process. The main aim of Kanban system is to delivered the exactly requirement of the process.

Kanban comes from the Japanese word which means visual card. Kanban system maintain and improve the efficiency of production.

Its purpose is satisfied the requirement of customers and control the quality of the production.

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How is everyone doing on this fine January da 12th?

Kay [80]

Great thanks for asking!

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3 years ago

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Info security:

il63 [147K]

Answer:

True

Explanation:

Dual home host - it is referred to as the firewall that is incorporated with two or more networks. out of these two networks, one is assigned to the internal network and the other is for the network. The main purpose of the dual-homed host is to ensure that no Internet protocol traffic is induced between both the network.

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4 years ago

The surface of an object is the<br> texture value appearance or function

maksim [4K]

Texture value appearance

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3 years ago

The pump of a water distribution system is powered by a 15-kW electric motor whose efficiency is 90 percent. The water flow rate

wariber [46]

Answer:

Mechanical power of pump is 74.07%.

Explanation:

Power of motor = 15 KW

Efficiency of motor= 90%

So the actual power(P) supplied by motor = 0.9 x 15 KW

P=13.5 KW

Water flow rate = 50 L/s

Volume flow rate = 50 L/s

We know that

$1000\ L/s=1\ m^3/s$

$Volume\ flow \rate =0.05\ m^3/s$

We know that pump is an open system and work input for open system can be calculated as

W=VΔP

ΔP is the pressure difference

V is the volume flow rate

So by putting the values

W=0.05 (300-100) (here ΔP=300 - 100=200 KPa)

W=10 KW

So mechanical power of pump

$\eta =\dfrac{W}{P}$

$\eta =\dfrac{10}{13.5}$

η =0.7407

Mechanical power of pump is 74.07%.

6 0

3 years ago

1 // Lab 2 tryIt2A 2 #include 3 using namespace std; 4 5 int main() 6 { int x = 1, y = 3; 7 int X = 2, Y = 4; 8 9 cout <<

padilas [110]

Answer:

Here is the complete program:

#include <iostream>

using namespace std;

int main()

{ int x = 1, y = 3;

int X = 2, Y = 4;

cout << "tryIt 2A" <<endl;

cout << x << y << endl;

cout << "x" << "y" << endl;

cout << X << " " << Y << endl;

cout << 2 * x + y << endl;

cout << 2 * X + Y << endl;

//cout << x + 2*y << endl;

cout << "x = ";

cout << x;

cout << " y = ";

cout << y;

return 0;

}

Explanation:

I will explain the code line by line in the comment with each line of code and the output of each cout statement.

int x = 1, y = 3;

This statement assigns value 1 to integer variable x and 3 to int variable y

int X = 2, Y = 4;

This statement assigns value 2 to integer variable X and 4 to int variable Y As C++ is a case sensitive language so variable x and y are different from variables X and Y.

cout << "tryIt 2A" <<endl;

This statement has cout which is used to display output on the screen. So the output displayed by this cout statement is:

tryIt2A

cout << x << y << endl;

This statement will print the values stored in x and y variables. So output displayed by cout statement here is 1 and 3. As there is not space or next line specified in the statement so output displayed will look like this:

cout << "x" << "y" << endl;

This statement will display x and y but these are not the variable x and y. They are enclosed in double quotation marks so they are treated as strings not variables so the output displayed is:

cout << X << " " << Y << endl;

This statement will print the values stored in X and Y variables. So output displayed by cout statement here is 2 and 4. As there is space " " specified in the statement so 2 and 4 are displayed with a space between them so the output displayed will look like this:

2 4

cout << 2 * x + y << endl;

This statement has an arithmetic operation in which 2 is multiplied by the values stored in variable x and then the result is added by value of y. So 2*1 = 2 and 2 + 3 = 5. So the result produced by this cout statement is:

cout << 2 * X + Y << endl;

This will work same as above cout statement but the only difference is that the values of capital X and Y variables are calculated here. So 2 * 2 = 4 and then 4 + 4 = 8. The result produced by this cout statement is:

//cout << x + 2*y << endl;

This is a comment because before this statement // is written which is used for single line comment. So compiler ignores comments and will not compile this statement.

cout << "x = ";

This will display "x = " as it is not variable but it is treated as a line to be displayed on the screen. So cout statement displays:

x =

cout << x;

This will print the value stored in x variable as there are no double quotes around x so it is a variable which contains value 1. In the above statement there is no endl so the output of this cout statement is displayed with the output of previous cout statement. So the following line is displayed on screen:

x = 1

cout << " y = ";

This will display "y = " as it is not variable but it is treated as a line to be displayed on the screen. In the above statement there is no endl so the output of this cout statement is displayed with the output of previous cout statement. So the following line is displayed on screen

x = 1 y =

cout << y;

This will print the value stored in y variable as there are no double quotes around y so it is a variable which contains value 3. In the above statement there is no endl so the output of this cout statement is displayed with the output of previous cout statement. So the following line is displayed on screen:

x = 1 y = 3

So the output of the entire program along with the program is attached as screenshot.

6 0

4 years ago