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mario62 [17]
2 years ago
12

A device is needed to accelerate a 3000 lb vehicle into a barrier with constant velocity to test its 5 mph bumpers. The vehicle

will start at rest, move forward, and have constant velocity for the last part of its motion before striking the barrier with the specified velocity.
Design a cam-follower system to do this. The vehicle will leave contact with your follower just prior to the crash.
Engineering
2 answers:
Alik [6]2 years ago
8 0

Answer:

The cam-follower system is designed such that the vehicle will move at a speed, v = \frac{Fgt}{W}

Explanation:

The vehicle starts at rest, u = 0 m/s

Some force, F, will be applied by the device on the truck

The force is given by the equation, F = ma

a = F/m..........(1)

The weight of the vehicle is given by W = mg

m = W/g.........(2)

Substituting equation (2) into (1)

a = F ÷ (W/g)

a = gF/W............(3)

The applied force makes the vehicle to move with constant velocity, v

From the equation of motion, v = u + at............(4)

v = 0 + (gF/W)t

v = \frac{Fgt}{W}

Arte-miy333 [17]2 years ago
5 0

Answer:

The device acceleration is

a = f/m = f/(w/g)=fg/w

The velocity v is

v= u +at

When u =o

v = at

Substitute the value of a

v = fgt/w

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Answer:

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W=-\int\limits^a_b {RT(1+\frac{B}{V} +\frac{C}{V^2}\frac{1}{V}  } \, dV

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(b) for Z = 1 + B' P +C' P^2 = PV/RT by performing differential we get  

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W=-\int\limits^a_b {P(RT(-1/p^2+0+C')} \, dP

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by substituting given limit and P = 1 bar , P2 = 50 bar and T = 373 K we get work  

W=12.59 kJ/mol

The work by differ between a and b because the conversion of constant of virial coefficients are valid only for infinite series  

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