A device is needed to accelerate a 3000 lb vehicle into a barrier with constant velocity to test its 5 mph bumpers. The vehicle
2 answers:
Answer:
The cam-follower system is designed such that the vehicle will move at a speed, v =
Explanation:
The vehicle starts at rest, u = 0 m/s
Some force, F, will be applied by the device on the truck
The force is given by the equation, F = ma
a = F/m..........(1)
The weight of the vehicle is given by W = mg
m = W/g.........(2)
Substituting equation (2) into (1)
a = F ÷ (W/g)
a = gF/W............(3)
The applied force makes the vehicle to move with constant velocity, v
From the equation of motion, v = u + at............(4)
v = 0 + (gF/W)t
v =
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Answer:
Speed of aircraft ; (V_1) = 83.9 m/s
Explanation:
The height at which aircraft is flying = 3000 m
The differential pressure = 3200 N/m²
From the table i attached, the density of air at 3000 m altitude is; ρ = 0.909 kg/m3
Now, we will solve this question under the assumption that the air flow is steady, incompressible and irrotational with negligible frictional and wind effects.
Thus, let's apply the Bernoulli equation :
P1/ρg + (V_1)²/2g + z1 = P2/ρg + (V_2)²/2g + z2
Now, neglecting head difference due to high altitude i.e ( z1=z2 ) and V2 =0 at stagnation point.
We'll obtain ;
P1/ρg + (V_1)²/2g = P2/ρg
Let's make V_1 the subject;
(V_1)² = 2(P1 - P2)/ρ
(V_1) = √(2(P1 - P2)/ρ)
P1 - P2 is the differential pressure and has a value of 3200 N/m² from the question
Thus,
(V_1) = √(2 x 3200)/0.909)
(V_1) = 83.9 m/s
Answer:
78 MPa
Explanation:
Given that the critical resolved shear stress for a metal is 39 MPa, the maximum possible yield strength for a single crystal of this metal is twice the critical resolved shear stress for the metal. The maximum yield yield strength for a single crystal of this metal that is pulled in tension () is given as: