<h3>
Answer:</h3>
2.572 g
<h3>
Explanation:</h3>
From the question;
Volume of Helium gas, V is 18.5 L
Pressure,P is 85.5 kPa
Temperature, T is 296 K
We are required to calculate the mass of Helium gas
<h3>Step 1: Calculate the number of moles of Helium gas </h3>
- This can be done using the ideal gas equation.
- The ideal gas equation is PV=nRT, where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant which is 8.314 kPa.L/K.mol
Rearranging the formula;
Thus,
n = 0.643 moles
Therefore, moles of Helium are 0.643 moles
<h3>Step 2: Calculate the mass of Helium gas </h3>
To calculate the mass we multiply the number of moles by the molar mass.
Mass = Number of moles × Molar mass
Molar mass of Helium = 4.00 g/mol
Therefore;
Mass of He = 0.643 moles × 4.00 g/mol
= 2.572 g
Hence, mass of helium gas is 2.572 g
Answer:
George Washington's presidential term lasted from April 30th, 1789 to March 4, 1797
The number of neutrons and protons together determines an elements mass number. Therefore, your answer would be C.
hope this helps!
According to the reaction equation:
PbCrO4 ↔ Pb2+ + CrO42-
so, when the Ksp expression = [Pb2+] [CrO42-]
when the Ksp =2.8 x 10^-13
when the solubility is the amount of solute that dissolved in a unit volume of a solvent so, we can assume solubility = X
by substitution on Ksp expression:
∴2.8 x 10^-13 = X*X
∴X = √(2.8 x 10^-13)
= 5.29 x 10^-7 M
∴ the solubility = X = 5.29 x 10^-7