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4 years ago

Crystal lattice definition

1 answer:

5 0

A geometric arrangement of the points in space at which the atoms, molecules, or ions of acrystal occur. Also called <span>space lattice</span><span>. Hope this helps</span>

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Pls help me with this question thank you

klemol [59]

Mass times acceleration

6 0

3 years ago

3- Um tipo de nutriente complexo presente

umka21 [38]

Answer:

The human body when metabolizing meat, milk or eggs, being high in protein, manufactures uric acid as a metabolite, and releases more urea in the urine.

Uric acid generates an increased retention of liquid or water, that is why people who ingest excessively meat suffer from GOTA disease.

Gout disease is systemic and life-threatening puffiness.

Furthermore uric acid is an organic compound of carbon, nitrogen, oxygen and hydrogen. Its chemical formula is C5H4N4O3. It is found in urine in small amounts.

And urea is defined as a renal parameter from the quantitative point of view; It is a colorless, crystalline chemical compound of formula CO (NH2) 2. It is found abundantly in urine and faeces.

Explanation:

To have an accurate idea of the function of the kidneys, it is sufficient to carry out a simple blood test with determination of Urea and creatinine and an analysis of a urine sample in which the presence of cells (red blood cells and leukocytes) is assessed. and / or proteins (albumin). Today these 2 types of analysis are part of the routine of any analytical study.

4 0

3 years ago

A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine

bagirrra123 [75]

Answer:

The final volume of the sample of gas $V_{2}$ = 0.000151 $m^{3}$

Explanation:

Initial volume $V_{1}$ = 200 ml = 0.0002 $m^{3}$

Initial temperature $T_{1}$ = 296 K

Initial pressure $P_{1}$ = 101.3 K pa

Final temperature $T_{2}$ = 336 K

Final pressure $P_{2}$ = K pa

Relation between P , V & T is given by

$P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }$

Put all the values in the above equation we get

$101.3 (\frac{0.0002}{296} )= 152 (\frac{V_{2} }{336} )$

$V_{2}$ = 0.000151 $m^{3}$

This is the final volume of the sample of gas.

4 0

4 years ago

Consider a balloon with volume V. It contains n moles of gas and has an internal pressure of P. The temperature of the gas is T.

Stels [109]

Given that the gas inside the balloon is an ideal gas, then the ideal gas equation can be used to describe the system. I think the correct answer from the choices listed above is option B. If the balloon is heatedto a temperature of 15.5T while it is placed under a high pressure of 15.5P, then the volume of the balloon stays the same since the change in temperature corresponds to same degree of change with pressure.

8 0

3 years ago

Read 2 more answers

One of the nuclides in each of the following pairs is radioactive. Predict which is radioactive and which is stable.a. 39/19K an

marishachu [46]

Answer:

a) 39/19 K : stable nuclide, 40/19 K : radioactive nuclide.

b) 209B: stable nuclide, 208Bi : radioactive nuclide

c) nickel-58 : stable nuclide, nickel-65 : radioactive nuclide.

Explanation:

As per the rule, nuclides having odd number of neutrons are generally not stable and therefore, are radioactive.

Mass number (A) = Atomic number (Z) + No. of neutrons (N)

Or, N = A - Z

39/19 K and 40/19 K

Calculate no. of neutrons in 39/19 K as follows:

atomic no. = 19, mass no. 39

N = 39 - 19

= 20 (even no.)

Calculate no. of neutrons in 40/19 K as follows:

atomic no. = 19, mass no. 40

N = 40 - 19

= 21 (odd no.)

Therefore, 39/19 K is a stable nuclide and 40/19 K is a radioactive

nuclide.

209Bi and 208Bi

Calculate no. of neutrons in 209Bi as follows:

atomic no. = 83, mass no. 209

N = 209 - 83

= 126 (even no.)

Calculate no. of neutrons in 208Bi as follows:

atomic no. = 83, mass no. 208

N = 208 - 83

= 125 (odd no.)

Therefore, 209Bi is a stable nuclide and 208Bi is a radioactive nuclide.

nickel-58 and nickel-65

Calculate no. of neutrons in nickel-58 as follows:

atomic no. = 28, mass no. 58

N = 58 - 28

= 30 (even no.)

Calculate no. of neutrons in nickel as follows:

atomic no. = 28, mass no. 65

N = 65 - 28

= 37 (odd no.)

Therefore,nickel-58 is a stable nuclide and nickel-65 is a radioactive nuclide.

5 0

3 years ago