Answer:
1.21 g of Tris
Explanation:
Our solution if made of a solute named Tris
Molecular weight of Tris is 121 g/mol
[Tris] = 100 mM
This is the concentration of solution:
(100 mmoles of Tris in 1 mL of solution) . 1000
Notice that mM = M . 1000 We convert from mM to M
100 mM . 1 M / 1000 mM = 0.1 M
M = molarity (moles of solute in 1 L of solution, or mmoles of solute in 1 mL of solution). Let's determine the mmoles of Tris
0.1 M = mmoles of Tris / 100 mL
mmoles of Tris = 100 mL . 0.1 M → 10 mmoles
We convert mmoles to moles → 10 mmol . 1mol / 1000mmoles = 0.010 mol
And now we determine the mass of solute, by molecular weight
0.010 mol . 121 g /mol = 1.21 g
Answer:
C
Explanation:
It is letter C since you are currently experimenting to see if by the amount of rainfall it gets it can <em><u>grow</u></em><em><u> </u></em><em><u>more</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>less</u></em>. So you control the amount of rain
I think the answer is B. I really don't remember but im pretty sure its that one.
Answer:
The plants at a light intensity of 1200 will produce more oxygen than the plants at 400.
Explanation:
