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Arte-miy333 [17]
3 years ago
8

Question 1 of 5

Physics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

solar energy warms most of the earths surface

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When a charged particle moves at an angle of 11° with respect to a magnetic field, it experiences a magnetic force of magnitude
rosijanka [135]
1) F=q[vB], where q -> charge, v-> velocity, B-> magnetic field. [ , ] -> cross product.
2) f=q*v*B*sin(11°) {1}
3) 1.6f=q*v*B*sin(alpha) {2}
4) {2} / {1} -> 1.6=sin(alpha)/sin(11°) or sin(alpha)=1.6*sin(11°) --> alpha=arcsin (1.6*sin(11°))
So, alpha=17.7°=18°
5 0
3 years ago
The ability to navigate, hunt, and communicate by electric current in water most likely helps make up for the effect of dark, mu
fgiga [73]
<span>The ability to navigate, hunt, and communicate by electric current in water most likely helps make up for the effect of vision. The answer to your question is VISION. 

</span>If fish live in a dark, murky water, that means that their sense of vision is affected. In dark, murky water they could not see anything. So, fish that lives in this kind of water developed the ability to <span>o navigate, hunt, and communicate by electric current in water. This ability is known as electroreception. Among fish, electroreception is present in some sharks and rays, and electric eels.</span><span>

I hope that this is the answer that you were looking for and it has helped you.

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6 0
4 years ago
A mule is harnessed to a sled having a mass of 246 kg, including supplies. The mule must exert a force exceeding 1210 N at an an
zimovet [89]

(a) 1800 N

The equation of the forces along the vertical direction is:

F sin \theta + N - mg = 0

where

F sin \theta is the component of the applied force along the vertical direction

N is the normal force on the sled

mg is the weight of the sled

Substituting:

F = 1210 N

m = 246 kg

\theta = 30.3^{\circ}

We find N:

N=mg-F sin \theta = (246)(9.8)-(1210)(sin 30.3^{\circ})=1800 N

(b) 0.580

The equation of the forces along the horizontal direction is:

F cos \theta - \mu_s N = 0

where

F cos \theta is the horizontal component of the push applied by the mule

\mu_s N is the static frictional force

Substituting:

F = 1210 N

N = 1800 N

\theta = 30.3^{\circ}

We find \mu_s, the coefficient of static friction:

\mu_s = \frac{F cos \theta}{N}=\frac{(1210)(cos 30.3^{\circ})}{1800}=0.580

(c) 522 N

In this case, the force exerted by the mule is

F= 6.05 \cdot 10^2 N = 605 N

So now the equation of the forces along the horizontal direction can be written as

F cos \theta - F_f = 0

where

\theta=30.3^{\circ}

and F_f is the new frictional force, which is different from part (b) (because the value of the force of friction ranges from zero to the maximum value \mu N, depending on how much force is applied in the opposite direction)

Solving the equation,

F_f = F cos \theta = (605)(cos 30.3^{\circ})=522 N

6 0
3 years ago
A wire 25 m long carries a current of 12 A from west to east. If the magnetic force on the wire due to Earth’s magnetic field is
ra1l [238]
<h2>Answer:</h2>

<em>1.33 x 10⁻ ⁴ T outwards.</em>

<em></em>

<h2>Explanation:</h2>

The equation for the magnetic force (F) on a wire whose length is L and carrying a current I in a magnetic field (B) that is uniform is given by;

F = ILB sin θ          ---------------------(i)

Where;

θ = angle between the direction of the current and that of the magnetic field.

From the question,

F = 4.0 × 10⁻² N

I = 12A

L = 25m

θ = 90°

<em>Substitute these values into equation(i) and solve as follows;</em>

4.0 × 10⁻² = 12 x 25 x B x sin 90°

4.0 × 10⁻² = 300 x B x 1

4.0 × 10⁻² = 300B

0.04 = 300B

B = \frac{0.04}{300}

B = 0.000133

B = 1.33 x 10⁻ ⁴ T

To get the direction of the magnetic field, the right-hand rule is used.

If the right hand fingers are positioned in the correct order specified by the right hand rule, then it would be seen that the magnetic field is directed outwards.

Therefore, the magnitude and direction of the magnetic field at this location is <em>1.33 x 10⁻ ⁴ T outwards.</em>

6 0
3 years ago
What separates the terrestrial planets from the jovian or gas planets in space?
Flura [38]
In our solar system, terrestrial planets are separated from the gas giants by the asteroid belt. The asteroid belt is a region in the solar system between Mars and Jupiter where asteroids are located. Gas giants do not have a solid surface and possible a small rocky core. The gas giants are Jupiter, Saturn, Uranus and Neptune. The first four planets, Mercury, Venus, Earth and Mars.  
8 0
3 years ago
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