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3 years ago

How could both phone and tv break in the collision?

Chemistry

1 answer:

Alina [70]3 years ago

4 0

Answer:

You could trip down and fall with your phone in your hand, however by accident you may throw your phone before hitting the ground to crack it and when you throw the phone, you could have directly thrown it at the tv and then the phone bounced off the tv caused by impact and hit the ground harshly causing the phone and tv to crack or break in the process and to add you might be also, hurt from the fall. Hope this helps :)

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What do you think will happen to the kidneys if any of these parts were damaged?

Lemur [1.5K]

Answer:

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3 years ago

When a strip of magnesium metal is placed in an aqueous solution of copper(II) nitrate, elemental copper coats the surface of th

Lera25 [3.4K]

Answer:

1. 2+ ( $Cu^{2+}$ ).

2. 0 ( $Cu^0$ ).

Explanation:

Hello,

In this case, the described chemical reaction is a redox reaction in fact, since the oxidation states of both magnesium and copper change as shown due to the displacement:

$Mg(s)+Cu(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+Cu(s)$

Therefore:

1. Since copper is the cation in the copper (II) nitrate, the (II) means that its charge is 2+ ( $Cu^{2+}$ ).

2. Since copper is alone, it means no electrons are being neither shared not given, its charge is 0 ( $Cu^0$ ).

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3 years ago

A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num

-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

$V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}$

$\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}$

B) Radius

$\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}$

$V = \frac{ 4}{3 }\pi r^{3}$

$r^{3} = \frac{3V }{4 \pi }\$

$r= \sqrt [3]{ \frac{3V }{4 \pi } }$

$r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}$

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3 years ago

State the relationship between electron configuration and location of an element in the period table

inn [45]

Answer:

elements in same group have same valence electron.

period of element is equal to valence shell

Explanation:

if the elements are in a same group then they will be having same number of valence electron.

the period of an element in periodic table is equal to the valence shell of the element. that is if the valence electron are in 3 rd shell then the element will be in third period.

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3 years ago

How could you safely determine if a base is stronger than an acid? Compare the taste of the base and the acid. Use a conductivit

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3 years ago

How could both phone and tv break in the collision?​

How could both phone and tv break in the collision?