All categories

3 years ago

An object becomes positively charged when it

2 answers:

5 0

A. loses electron, bc electrons are negatively charged, protons are positively charged, when electrons are lost, that means there are more protons more

andrezito [222]3 years ago

4 0

<u>Answer:</u> The correct answer is Option a.

<u>Explanation:</u>

There are 3 sub-atomic particles in an atom.

1.) Protons: These particles are positively charged particles and are present inside the nucleus.

2.) Electrons: These particles are negatively charged particles and are present around the nucleus. These can be easily lost or gained. When the electrons are lost, the atom will gain a positive charge and when electrons are gained, the atom will carry a negative charge.

3.) Neutrons: These particles does not carry any charge on them and their loss or addition will not cause any effect on the atom.

Hence, the correct answer is option a.

You might be interested in

What assumptions do we make in order to use the Henderson-Hasselbalch equation? a. Both the weak acid and its conjugate base are

zepelin [54]

Answer:

The final and initial concentration of the acid and it's conjugate base are approximately equal, that is we use the weak acid approximation.

Explanation:

The Henderson-Hasselbalch is used to calculate the pH of a buffer solution. It depends on the weak acid approximation.

Since the weak acid ionizes only to a small extent, then we can say that [HA] ≈ [HA]i

Where [HA] = final concentration of the acid and [HA]i = initial concentration of the acid.

It also follows that [A^-] ≈ [A^-]i where [A^-] and[A^-]i refer to final and initial concentrations of the conjugate base hence the answer above.

7 0

3 years ago

_________feedback is a type of feedback in which a system is triggered to produce an output.

stiv31 [10]

Answer:

positive

Explanation:

3 0

3 years ago

Read 2 more answers

What is the [OH-] in a solution if the [H*] = 1.2 x 10-3 M?

spayn [35]

We know that [OH⁻] * [H⁺] = 10⁻¹⁴

plugging the value of [H⁺]

[OH⁻] * 1.2 * 10⁻³ = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ * (10³/1.2)

[OH⁻] = 833.3 * 10⁻¹⁴

[OH⁻] = 8.33 * 10⁻¹²

7 0

3 years ago

calculate the amount of energy (in kJ) to convert 337 grams of liquid water from 0 degrees celsius to water vapor at 177 degrees

Ghella [55]

Do you have any options

3 0

4 years ago

Read 2 more answers

An element has five isotopes. Calculate the atomic mass of this element using the information below. Show all your work. Using t

Katena32 [7]

Answer: Sol:-

Data provided in the question is :-

Atomic mass of isotope -1 = 64 amu

Atomic mass of isotope -2 = 66 amu

Atomic mass of isotope -3 = 67 amu

Atomic mass of isotope -4 = 68 amu

Atomic mass of isotope - 5 = 70 amu

Percentage abundace of isotope - 1 = 48.89 %

Percentage abundance of isotope -2 = 27.81 %

Percentage abundance of isotope - 3 = 4.11%

Percentage abundance of isotope-4 = 18.57%

Percentage abundance of isotope - 5 = 0.62 %

Formula used :-

Average atomic mass of an element =[ {(atomic mass of isotope-1 * percentage abundance of isotope-1) + ( atomic mass of isotope-2 * percentage abundance of isotope -2) + ( atomic mass of isotope -3 * percantege abundance of isotope-3 ) + ( atomic mass of isotope-4 * percentage abundance of isotope-4) + (atomic mass of isotope-5 * percentage abundance of isotope-5)} / 100]

Calculation :-

Put all the value in the formula :-

Average atomic mass of an element = [{(64 * 48.89) + (66 * 27.81) + (67 * 4.11) + (68 * 18.57) + (70 * 0.62)} / 100] amu

= [{(3128.96) + (1835.46) +(257.37) + (1262.76) + (43.4)} / 100] amu

= {(6528.04) / 100} amu

= 65.2804 amu

Average atomic mass of an element is = 65.2804 amu

Then this mass is approximatly equal to atomic mass of zinc so this element would be zinc

atomic mass of zinc = 65.38 \approx 65.2804 amu

5 0

3 years ago