The planet MARS is visible without a telescope on many clear nights. The planets JUPITER, MERCURY, VENUS and SATURN are also viewable without the aid of magnification.
(a) g = Gm/r^2
where G=6.67 * 10^-11 Nm^2/kg^2,
m is the mass of the planet,
r is the radius of the planet.
7.0 = (6.67 * 10^-11)/(2500^2) * m
m= (25000000^2 * 9.0)/(6.67 * 10^-11)
m = 8.4333 x 10^24 kg
(b) g=Gm/r^2. This time, the radius is 2500+10000 = 12500km g = (6.67 * 10^-11 * 8.43333*10^18)/(12500^2)
g = 3.6 m/s^2
Answer:
5p
Explanation:
We are given that a tin has 50 electrons.
We have to find in which subshell electrons experience the lowest effective nuclear charge.
We know that the electron in outermost shell experience the lowest effective nuclear charge.
Electronic configuration is given by
Outer most sub-shell is 5p. Therefore, 5p subshell experience the lowest effective nuclear charge because the distance of 5p sub-shell is large from nucleus.
Answer: 5p
Answer:
<h3>a) </h3><h3>
<u>Question</u><u>:</u><u>-</u></h3>
- Rubber is a good conductor of electricity.
<h3>
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u></h3>
- <em>I</em><em>t</em><em>'</em><em>s</em><em> </em><em>i</em><em>n</em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>s</em><em>e</em><em>n</em><em>t</em><em>e</em><em>n</em><em>c</em><em>e</em><em>.</em>
- As we know that, rubber are an insulators of electricity, and they do not not have free ions which can help in conducting electricity.
<u>S</u><u>o</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>s</u><u>e</u><u>n</u><u>t</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>i</u><u>s</u><u>:</u>
- <em>R</em><em>u</em><em>b</em><em>b</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>a</em><em> </em><em>b</em><em>a</em><em>d</em><em> </em><em>c</em><em>o</em><em>n</em><em>d</em><em>u</em><em>c</em><em>t</em><em>o</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>r</em><em>i</em><em>c</em><em>i</em><em>t</em><em>y</em><em>.</em>
<h3>b)</h3><h3>
<u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u></h3>
- Electroplating wastes are useful to human health and environment.
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
- <em>It's</em><em> </em><em>incorrect</em><em> </em><em>sentence</em><em>.</em><em> </em>
- As we know that, electroplating of substances releases harmful and toxic substances into the environment causing serious health issues in human, so it's waste substances released into environment can have very harmful effects.
<u>So correct sentence is:</u>
- <em>Electroplating wastes are </em><em>harmful</em><em> </em><em>to human health and </em><em>environment</em><em>.</em>
<h3>
c)</h3><h3>
<u>Question</u><u>:</u><u>-</u></h3>
- In an LED bulb, the shorter lead is connected to the positive terminal of the battery.
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
- <em>It's incorrect sentence. </em>
- As we know that, in an LED bulb their are two terminals that is the positive and the negative. So here the lead connected to the positive terminal is always slightly longer than the lead connected to negative terminal of the bulb.
<u>So correct sentence is:</u>
- <em>In an LED bulb, the </em><em>longer</em><em> lead </em><em>i</em><em>s</em><em> </em><em>connected to the positive terminal of the battery.</em>
<h3>
d)</h3><h3>
<u>Question</u><u>:</u><u>-</u></h3>
- Pure water conducts electricity.
<h3>
<u>Answer</u><u>:</u><u>-</u></h3>
- <em>It's incorrect sentence. </em>
- As we know that, pure water is a form of H2O where Hydrogen (H) is positive ion and Oxygen (O) is a negative ion which can conduct electricity when they are in individuals but as in pure water they are in combined form of compound H2O in which they become neutral and can't conduct any electricity.
<u>So correct sentence is:</u>
- <em>P</em><em>ure water </em><em>c</em><em>a</em><em>n</em><em>'</em><em>t</em><em> </em><em>conduct</em><em> </em><em>electricity.</em>
The surface is frictionless, so there is no frictional force acting on the ball. There are no other forces acting on the ball in the horizontal direction, so it's a uniform motion with constant speed. Therefore, the velocity of the ball will remain the same for the entire duration of the motion, and so after 5 seconds the velocity is still 15 m/s.