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Elis [28]
3 years ago
8

A 39-cm-long vertical spring has one end fixed on the floor. Placing a 2.2 kg physics textbook on the spring compresses it to a

length of 29 cm. What is the spring constant?
Physics
1 answer:
Inessa05 [86]3 years ago
7 0

Answer:

The spring constant is 215.6 N/m.

Explanation:

Given that,

Distance = 39 cm

Compresses length = 29 cm

Mass = 2.2 kg

We need to calculate the distance

Using formula of distance

x=l-l'

Put the value into the formula

x=39-29=10\ cm

We need to calculate the spring constant

Using formula of restoring force

F=kx

k=\dfrac{mg}{x}

Where, F = force

x = distance

Put the value into the formula

k=\dfrac{2.2\times9.8}{10\times10^{-2}}

k=215.6\ N/m

Hence, The spring constant is 215.6 N/m.

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KatRina [158]

Answer:

2.2kg

Explanation:

kilograms is a measurement of mass so the answer is 2.2kg

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3 years ago
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How much heat is absorbed by a 71g iron skillet when its temperature rises from 11oC to 29oC?
diamong [38]
The right formula to use for this calculation is the heat capacity formula, 
Heat absorbed, Q = MCT, Where 
M = Mass of the substance = 71
C = Specific heat capacity for iron = 0.450 J/gc
T = Change in temperature = 29 - 11 = 18
Q = 71 * 0.450 *18 = 575.10
The amount of heat absorbed by the iron skillet is 575 J.
5 0
3 years ago
determine the amount of potential energy of a 5.0-N book that is moved to three different shelves on a bookcase . the height of
klasskru [66]
Potential energy<span> is the </span>energy<span> that is stored in an object due to its position relative to some zero position. It is calculated by the expression PE = mgh where mg is the weight of the book and h is the height. It is calculated as follows:

PE = 50(1) = 50 J
</span>PE = 50(1.5) = 75 J
PE = 50(2) = 100 J
7 0
3 years ago
2 objects have a total momentum of 400kg m/s, they collide. Object A’s mass is5kg &amp; object B’s mass is 11kg. After the colli
ss7ja [257]

Answer:

Explanation:

We shall apply law of conservation of momentum .

Momentum before collision = momentum after collision .

Momentum before collision = 400 kg m/s

Momentum after collision = 5  x v + 11 x 15

where v is velocity of A after the collision .

5  x v + 11 x 15 = 400

5 v = 400 - 165

5v = 235

v = 47 m /s .

3 0
3 years ago
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