A 39-cm-long vertical spring has one end fixed on the floor. Placing a 2.2 kg physics textbook on the spring compresses it to a
1 answer:
Answer:
The spring constant is 215.6 N/m.
Explanation:
Given that,
Distance = 39 cm
Compresses length = 29 cm
Mass = 2.2 kg
We need to calculate the distance
Using formula of distance
Put the value into the formula
We need to calculate the spring constant
Using formula of restoring force
Where, F = force
x = distance
Put the value into the formula
Hence, The spring constant is 215.6 N/m.
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Answer:
0.5A
Explanation:
Using ,
R is the resistance (in Ohms)
V is the voltage (in V)
I is the current (in A)
I = 0.5A
Answer:
y = 77.74 10⁻⁵ m
Explanation:
For this exercise we can use Newton's second law
F = m a
a = F / m
a = 4.9 10⁻¹⁶ / 9.1 10⁻³¹
a = 0.538 10¹⁵ m / s
This is the vertical acceleration of the electron.
Now let's use kinematics to find the time it takes to move the
x= 29 mm = 29 10⁻³ m
On the x axis
v = x / t
t = x / v
t = 29 10⁻³ / 1.7 10⁷
t = 17 10⁻¹⁰ s
Now we can look for vertical distance at this time.
y = t + ½ a t²
y = 0 + ½ 0.538 10¹⁵ (17 10⁻¹⁰)²
y = 77.74 10⁻⁵ m