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3 years ago

Analyze why a body undergoing uniform motion eventually comes to rest even in the

Physics

1 answer:

djverab [1.8K]3 years ago

8 0

Answer:

It happens due to force of friction

Explanation:

If a body is performing a uniform motion and no external unbalanced force appears to apply on it, then the body will come to rest after certain time. The reason behind this is the force of friction that is applied in opposite direction of the motion. So, when there is no apparent unbalanced force it means that the only force acting on the body is the force of friction. This force of friction tends to stop the motion after some period of time, because it is acting in the direction opposite to that of motion.

Hence, the reason behind a body undergoing uniform motion eventually stops is <u>Force of Friction.</u>

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A thin metallic spherical shell of radius 0.357 m has a total charge of 5.03 times 10^-6 C placed on it. At the center of the sh

Artyom0805 [142]

Answer:

The electric field is $5.623\times10^{4}\ N/C$

Explanation:

Given that,

Radius = 0.357 m

Charge $Q=5.03\times10^{-6}\ C$

Point charge $q=4.15\times10^{-6}\ C$

Distance = 0.815 m

We need to calculate the total electric field

Using formula of electric field

$E=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q}{r^2}$

Where, q = point charge

r = distance

Put the value into the formula

$E=\dfrac{9\times10^{9}\times4.15\times10^{-6}}{(0.815)^2}$

$E=5.623\times10^{4}\ N/C$

Hence, The electric field is $5.623\times10^{4}\ N/C$

4 0

3 years ago

What is the sound intensity level in decibels? Use the usual reference level of I0 = 1.0×10−12 W/m2.

jek_recluse [69]

Answer:

L = 130 decibels

Explanation:

The computation of the sound intensity level in decibels is shown below:

According to the question, data provided is as follows

I = sound intensity = 10 W/m^2

I0 = reference level = $1 \times 10-12 W/m^2$

Now

Intensity level ( or Loudness)is

$L = log10 \frac{I}{10}$

$L = log10 \frac{10}{1\times 10^{-12}}$

$L = log10 \times 1013$

$= 13 \times 1 ( log10(10) = 1)$

Therefore

L = 13 bel

And as we know that

1 bel = 10 decibels

So,

The Sound intensity level is

L = 130 decibels

5 0

3 years ago

Two workers are sliding 350 kgkg crate across the floor. One worker pushes forward on the crate with a force of 390 NN while the

svetoff [14.1K]

Answer:

$\mu_k=0.18$

Explanation:

First, we write the equations of motion for each axis. Since the crate is sliding with constant speed, its acceleration is zero. Then, we have:

$x: T+F-f_k=0\\\\y:N-mg=0$

Where T is the tension in the rope, F is the force exerted by the first worker, f_k is the frictional force, N is the normal force and mg is the weight of the crate.

Since $f_k=\mu_k N$ and $N=mg$ , we can rewrite the first equation as:

$T+F-\mu_k mg=0$

Now, we solve for $\mu_k$ and calculate it:

$\mu_k=\frac{T+F}{mg}\\ \\\mu_k =\frac{220N+390N}{(350kg)(9.8m/s^{2})} =0.18$

This means that the crate's coefficient of kinetic friction on the floor is 0.18.

6 0

3 years ago

Suppose that the process were repeated, except that in step 3 a neutral acrylic rod instead of a finger is used to touch the ele

Marta_Voda [28]

Answer:

b) True Only if the finger is isolated from ground

c) True. The total charge does not change since the system is isolated

Explanation:

When the electroscope is touched with an acrylic rod, some charges are transferred from the electroscope to the rod, until the charge in both is equal.

In the case it know when the electroscope is touched with a finger, two things can happen.

- The body is isolated from the ground, the efective charge is redistributed between the two bodies. Case similar to insulating rod

- The body is connected to ground, the charge is transferred to the finger and from here to the ground until the total charge is transferred and the Earth and the final charge of the electroscope is zero.

Let's review the final statements

a) False, when part of the load is touched, it passes to the rod, so when it separates it does not return to the initial load

b) True Only if the finger is isolated from ground

c) True. The total load does not change since the system is isolated

d) False. The value of the load changes =, but its sign does not

8 0

3 years ago

A liquid thermometer can be used to test for fevers. When body temperature increases, the liquid inside the thermometer expands

kompoz [17]

Answer:

Explanation:

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4 0

3 years ago