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Shtirlitz [24]
3 years ago
12

HELP ASAP PLEASE! THIS IS FOR STUDY ISLAND

Chemistry
2 answers:
djverab [1.8K]3 years ago
5 0

Answer:

Copper

Explanation:

Given parameters:

Mass of metal = 25g

Volume of metal = 2.83cm³

Unknown:

Density of the metal  = ?

Solution:

Density is the mass unit volume of a substance. To solve this problem, use the mathematical expression below;

   Density  = \frac{mass}{volume}

mass is the amount of substance in the metal

volume is the space occupied by the metal

 Now solve;

    Density  = \frac{25}{2.83}   = 8.83g/cm³

The metal is Copper

valentina_108 [34]3 years ago
5 0

Answer:

lead

Explanation:

Density (D) is calculated by dividing the mass (m) of the substance by its volume(v):

D = m/v

11.34 g/cm3 = 8.96 g / 0.79 cm3

To find the identity of a substance, compare the calculated density to the values listed in the table. A sample with a density of 11.34 g/cm3 would be lead.

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nickel on the opther hand is also a metal but does not conduct a lot of electricy.

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3 years ago
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Hydrogen is a possible future fuel. However, elemental hydrogen is rare, so it must be obtained from a hydrogen- containing comp
dimulka [17.4K]

Answer:

1.1 × 10² g

Explanation:

First, we will convert 1.0 L to cubic centimeters.

1.0 L × (10³ mL/1 L) × (1 cm³/ 1 mL) = 1.0 × 10³ cm³

The density of water is 1.0 g/cm³. The mass corresponding to 1.0 × 10³ cm³ is:

1.0 × 10³ cm³ × (1.0 g/cm³) = 1.0 × 10³ g

1 mole of water (H₂O) has a mass of 18 g, consisting of 2 g of H and 16 g of O. The mass of Hydrogen in 1.0 × 10³ g of water is:

1.0 × 10³ g H₂O × (2 g H/18 g H₂O) = 1.1 × 10² g

4 0
3 years ago
According to Niels Bohr, electrons travel around an atom's nucleus in well-defined orbits.
Bas_tet [7]

Answer: The answer is B

Explanation:

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What substance is added during hydrolysis in order to break down food macromolecules?
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So, water (in terms of the word) is added to help split and breakdown macromolecules. 

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3 years ago
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What is the standard enthalpy of a reaction for which the equilibrium constant is (a) doubled, (b) halved when the temperature i
Alexxandr [17]

Answer:

a) 48KJ

b) -48KJ

Explanation:

Given that;

ln(K2/K1) = ΔH°/R(1/T2 - 1/T1)

K2= equilibrium constant at T2

K1 = equilibrum constant at T1

R = gas constant

T1 = initial temperature

T2 = final temperature

When we double the equilibrium constant K1; K2 = 2K1

T1 = 310 K

T2 = 310 + 15 = 325 K

ln(2K1/K1) =- ΔH°/R(1/T2 - 1/T1)

ln2 = -ΔH°/8.314(1/325 - 1/310)

0.693 = -ΔH°/8.314(3.08 * 10^-3 - 3.2 * 10^-3)

0.693 = -ΔH°/8.314 (-0.00012)

0.693 = 0.00012ΔH°/8.314

0.693 * 8.314 = 0.00012ΔH°

ΔH° = 0.693 * 8.314/0.00012

ΔH° = 48KJ

b) K2 =K1/2

ln(K1/2/K1) =- ΔH°/R(1/T2 - 1/T1)

ln (1/2) = -ΔH°/8.314 (1/325 - 1/310)

-0.693 = -ΔH°/8.314  (-0.00012)

-0.693 = 0.00012ΔH°/8.314

-0.693 * 8.314 = 0.00012ΔH°

ΔH°= -0.693 * 8.314/0.00012

ΔH°= -48KJ

6 0
3 years ago
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