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pav-90 [236]
3 years ago
7

Sodium (Na) A Homogeneous Mixture B Element C Compound D Heterogeneous Mixture

Chemistry
1 answer:
laiz [17]3 years ago
3 0
Sodium is categorized as a B. Element.
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(a) How much negative charge is on each oxygen of the carbonate ion?
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The chemical formula of a carbonate ion is CO3^2-. It is an AX3 system which means it take the trigonal planar shape. There would be two single bonds of C-O and one double bond C-O in order for C to agree with the octet rule. Two minus charges are equally distributed to the three oxygen atoms so that each oxygen of the carbonate ion would have a charge of negative 2/3.
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What is cis-3-Hexene?
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cis-3-Hexene is a symmetrical cis-disubstituted alkene that can be prepared by the hydroboration of 3-hexyne followed by protonolysis

I got this from Sigmaaldrich.com.

Not my work.

Hope it helps

7 0
3 years ago
Although there are different ways to approach a scientific investigation, all scientific investigations begin with some sort of
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Answer: hypothesis or guess

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3 years ago
Read 2 more answers
the chloride of a metal M contains 47.25% of metal 1.0 gram of metal would be displaced from a compound by 0.88 gram of another
GenaCL600 [577]

Answer:

The equivalent weight of M is approximately 31.8 g

The equivalent weight of N is approximately 27.98 g

Explanation:

The given parameters are;

The percentage of the the metal M in in the chloride = 47.25%

Where by the chemical formula for the metal chloride is MClₓ, we have;

47.25% of the mass of MClₓ = Mass of M = W

Therefore, we have;

\dfrac{0.4725}{W} = \dfrac{1}{W + 35.5 \cdot x}

0.4725 × (W +  35.5·x) = W

0.4725·W + 0.4725×35.5×x = W

W - 0.4725·W  = 16.77·x

0.5275·W = 16.77·x

W/x = 16.77/0.5275 = 31.799 = The equivalent weight of M

The equivalent weight of M = 31.799 ≈ 31.8 g

Given that 1 gram of M is displaced by 0.88 gram of N, then the equivalent weight of N that will displace 31.799 = 0.88 × 31.799 ≈ 27.98 g

The equivalent weight of N = 27.98 g.

7 0
2 years ago
If you have 2.4L of SO2 gas (at STP) how many moles of sulfur dioxide do you have?
Andru [333]

Answer:

0.107 mole of SO2.

Explanation:

1 mole of a gas occupy 22.4 L at standard temperature and pressure (STP).

With the above information, we can simply calculate the number of mole of SO2 that will occupy 2.4 L at STP.

This can be obtained as follow:

22.4 L contains 1 mole of SO2.

Therefore, 2.4 L will contain = 2.4/22.4 = 0.107 mole of SO2.

Therefore, 0.107 mole of SO2 is present in 2.4 L at STP.

4 0
3 years ago
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