Answer:
The heat of vaporisation of methanol is "3.48 KJ/Mol"
Explanation:
The amount of heat energy required to convert or transform 1 gram of liquid to vapour is called heat of vaporisation
When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.
Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is =
= 3.48 KJ
So, the heat of vaporization
Therefore, the heat of vaporization of methanol is 3.48KJ/Mol
From n=3 to n=1
<span>according to extension of the Wavelength in electron transition from n=3 to n=1 </span>
The sequence which represents the relationship between temperature and volume:
higher temperature --> more kinetic energy --> more space between particles higher volume
Explanation:
The above sequence is based on the Charles' law. This law states that at "a fixed mass of gas" and "at constant pressure", volume is directly proportional to temperature.
When the molecules in a container "collide with the wall", the pressure and momentum increase. Due to the increase in temperature the kinetic energy also increases. Thus, when the "momentum perpendicular" to the wall of the container is reversed it will have larger value. To reduce the rate of the collisions and to keep the pressure constant, the volume will have to be bncreased.
Base on the question and in my further research and investigation about the said problem that states to identify the type of bonding in solid potassium, I would say that the bondings are metallic bonding and metallic. I hope you are satisfied with my answer and feel free to ask for more