To test paint quality, scientists designed an experiment where the paint was exposed to temperatures ranging from 260 degrees Ce
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Answer:
1. C. remains the same. 2. C. is less than Kc. 3. B. run in the reverse direction to reestablish equilibrium. 4. A. increase.
Explanation:
At constant temperature, the equilibrium concentration has not effect on the equilibrium constant because the rate constants do not change with change in the concentrations or amounts of the reactants or products. Change in the concentration of one reactant or product causes the concentration of the others to change so as to maintain a constant value for the equilibrium constant. On the other hand, the reaction quotient is used to measure the relative amounts of reactants and products during a chemical reaction at any point in time. The value of the reaction quotient shows the direction of the chemical reaction.
Therefore, when 0.31 moles of CCl4(g) are removed from the equilibrium system at constant temperature:
1. the value of Kc remains the same
2. the value of Qc is less than Kc
3. the reaction must run in the reverse direction to reestablish equilibrium
4. the concentration of will increase because product will be converted to reactants to reestablish equilibrium.
Given that:
- At 25C the density of water is 0.997044 g/mL.
From the information attached below, we have the following parameters.
The density of water calculation using a bottle.
Initial volume of Final volume of Mass of water Density (g/mL)
burette (mL) burette (mL) dispensed (g)
Sample 1 2.33 7.34 5.000 -----
Sample 2 7.34 12.37 5.025 -----
Sample 3 12.37 18.50 6.112 -----
Sample 4 18.50 24.57 6.064 -----
Sample 5 24.57 31.31 6.720 -----
The first thing we need to do is to determine the change in the volume of the burette in each sample from the above information.
- The change in the volume of the burette = (final volume - the initial volume) mL
Sample 1:
= (7.34 - 2.33) mL
= 5.01 mL
Sample 2:
= (12.37 - 7.34) mL
= 5.03 mL
Sample 3:
= (18.50 - 12.37) mL
= 6.03 mL
Sample 4:
= (24.57 - 18.50) mL
= 6.07 mL
Sample 5:
= (31.31 - 24.57) mL
= 6.74 mL
The mass of the water dispersed in sample 1 is given as = 5.000 g
Using the relation for calculating the density of each, we have:
Sample 1
density = 0.998004 g/ml
Sample 2:
density = 0.999006 g/ml
Sample 3:
density = 0.997064 g/ml
Sample 4:
density = 0.999012 g/ml
Sample 5:
density = 0.997033 g/ml
Thus, the average density for all the samples is:
= 0.998024
∴
The percentage error for the two densities measurement is:
Given that the theoretical value = 0.997044 g/ml
Then;
= 0.0983%
Therefore, we can conclude that the percent error for the two density measurements is 0.0983%
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