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finlep [7]
3 years ago
14

The Earth's moon is unusually large. Two popular theories of the moon's origin include the "sister world" hypothesis, which stat

es that the moon formed from the same materials as the Earth, near enough to the Earth that they fell into orbit around each other. A second theory is the "capture" hypothesis, in which the moon formed elsewhere in the Solar system, and the Earth's gravity pulled it into its orbit. Studies of what the moon is made of indicate that some of its materials had to come from the Earth or from the same area of the Solar system where the Earth had formed. At the same time, the moon does not contain much of the material that makes up the Earth's core, so the moon could not have formed from the same materials as the Earth. How do the two facts above affect the described theories of the moon's origin? A. They show that scientists will never agree on where the moon came from. B. They show that more experiments on moon formation need to be done. C. They show that no theory accounts for the existence of the moon. D. They show that neither theory is complete and entirely correct.
Chemistry
2 answers:
Verizon [17]3 years ago
8 0

Answer: D. They show that neither theory is complete and entirely correct.

Explanation:

Theory is the set of rules and principles that describe and explain a particular phenomenon (the existence of the moon in this case) and is subject to changes as new evidence emerges that gives meaning to it.

In this sense, there are many theories about the Earth's moon formation and two of the "accepted" theories are described before the question. In addition, both theories explain in a certain way the reason why the Moon is predominantly composed of elements similar to those found on Earth.

However, both theories seem to be incomplete when trying to explain our Moon's origin.

Alex787 [66]3 years ago
4 0

Answer:

d

Explanation:

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2 years ago
C12H22011+1202-->12CO2+11H20
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Answer:

0.185moles

Explanation:

Given parameters:

Volume of O₂  = 49.8L

Unknown:

Number of moles of sucrose required  = ?

Solution:

We can assume that the reaction takes place at standard temperature and pressure.

From this, we can find the number of moles of oxygen that reacted and extrapolate to that of sucrose.

Chemical equation;

           C₁₂H₂₂0₁₁  +  120₂   →   12CO₂   +   11H₂0

Number moles  = \frac{volume of gas}{22.4}   at STP

Number of moles of oxygen gas = \frac{49.8}{22.4}   = 2.22moles

           12 moles of oxygen gas combines with  1 mole of sucrose

       2.22 moles of oxygen gas will combine with \frac{2.22}{12}   = 0.185moles

4 0
3 years ago
Which of the following is not a correct formula? A)Ba2O B)Ca3N2 C)KCl D)Li2S
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Answer:- A. Ba_2O is not the correct formula.

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2 years ago
rate of a certain reaction is given by the following rate law: rate Use this information to answer the questions below. What is
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Complete Question

The  rate of a certain reaction is given by the following rate law:

            rate =  k [H_2][I_2]

rate Use this information to answer the questions below.

What is the reaction order in H_2?

What is the reaction order in I_2?

What is overall reaction order?

At a certain concentration of H2 and I2, the initial rate of reaction is 2.0 x 104 M / s. What would the initial rate of the reaction be if the concentration of H2 were doubled? Round your answer to significant digits. The rate of the reaction is measured to be 52.0 M / s when [H2] = 1.8 M and [I2] = 0.82 M. Calculate the value of the rate constant. Round your answer to significant digits.

Answer:

The reaction order in H_2 is  n =  1

The reaction order in I_2 is  m = 1

The  overall reaction order z =  2

When the hydrogen is double the the initial rate is   rate_n  =  4.0*10^{-4} M/s

The rate constant is   k = 35.23 \  M^{-1} s^{-1}

Explanation:

From the question we are told that

   The rate law is  rate =  k [H_2][I_2]

   The rate of reaction is rate =  2.0 *10^{4} M /s

Let the reaction order for H_2 be  n and for I_2  be  m

From the given rate law the concentration of H_2 is raised to the power of 1 and this is same with I_2 so their reaction order is  n=m=1

   The overall reaction order is  

               z  = n +m

               z  =1 +1

               z  =2

At  rate =  2.0 *10^{4} M /s

        2.0*10^{4}  = k  [H_2] [I_2] ---(1)

= >    k  = \frac{2.0*10^{4}}{[H_2] [I_2]  }

given that the concentration of hydrogen is doubled we have that

            rate  = k [2H_2] [I_2] ----(2)

=>      k = \frac{rate_n  }{ [2H_2] [I_2]}

 So equating the two k

           \frac{2.0*10^{4}}{[H_2] [I_2]  } = \frac{rate_n  }{ [2H_2] [I_2]}

    =>    rate_n  =  4.0*10^{-4} M/s

So when

      rate_x =  52.0 M/s

        [H_2] = 1.8 M

         [I_2] =  0.82 \ M

We have

      52 .0 =  k(1.8)* (0.82)

     k = \frac{52 .0}{(1.8)* (0.82)}

      k = 35.23 M^{-2} s^{-1}

     

     

3 0
2 years ago
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