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Dmitry_Shevchenko [17]
3 years ago
15

Describe how gasoline, as a fuel, can undergo a chemical change.

Chemistry
1 answer:
kvasek [131]3 years ago
5 0

Answer with Explanation:

A "chemical change" occurs when the structure of the molecules change. If there's no change in structure, it is called a "physical change." This also means that a <em>chemical reaction </em>has to occur for something to be considered a chemical change.

Gasoline when used as a fuel is being transformed into other forms of energy. It undergoes a process called <em>"combustion."</em>

When used as a fuel for cars, <em>the gasoline is being burned to produce </em><u><em>heat energy.</em></u> This energy is then converted into <u><em>mechanical energy</em></u> that allows the car to move. Clearly, the gasoline has undergone a chemical change.

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4.2g of sodium bicarbonate is equivalent to how many moles of sodium bicarbonate
Mnenie [13.5K]
<span>The mass of one mole of sodium bicarbonate (aka NaHCO3) is equal to 1 * 22.99g/mol + 1 * 1.00g/mol + 1 * 12.01g/mol + 3 * 16.00g/mol = 83.91g/mol. From this, we can convert 4.2g of NaHCO3 to moles by dividing by 83.91g/mol, to get 0.050 moles of sodium bicarbonate.</span>
7 0
4 years ago
Read 2 more answers
12 Describe In your own words, describe the glassblowing process.
Vikentia [17]

Explanation:

To give the glass its final shape and size, it is blown into with a blowpipe, creating a sort of bubble of glass. To carry out this process, the blowpipe holding the glass must be placed on a steel stand. Then, the glass artist has to blow into the blowpipe while rotating it at the same

4 0
2 years ago
What is the mass in grams of 0.7350 moles of sodium?
Alik [6]

Answer:

Explanation:

1 mol of sodium = 23 grams (use the number on your periodic table).

0.7350 mol sodium = x

Cross multiply

1*x = 0.7350 * 23

x = 16.905

You will get slightly less than this, depending on your periodic table. But the method will be the same.

4 0
3 years ago
Consider two compounds. Compound A contains 15.7 g of sulfur and 18.6 g of fluorine. Compound B contains 25.4 g of sulfur and 60
Lunna [17]

Answer:

No, compound A and B are not the same compound

Explanation:

According to the law of definite proportion "every chemical compound contains fixed and constant proportions (by mass) of its constituent elements." (Encyclopedia Britannica)

We can see in the question that the ratio of flourine to sulphur in compound A is 1.18 while the ratio of flourine to sulphur in compound B is 2.37.

The two chemical compounds do not contain a fixed proportion by mass of their constituent elements therefore, they can not be same compound according to the law of definite proportions.

4 0
3 years ago
For the reactions system 2H2(g) + S2(g) 2H2S(g), a 1.00 liter vessel is found to contain 0.50 moles of H2, 0.020 moles of S2, an
Mnenie [13.5K]

Answer: 1) 2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)

Equilibrium constant is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.

K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}

where [] = concentration in Molarity=\frac{moles}{\text {Volume in L}}

Thus [H_2S]=\frac{68.5}{1.0}=68.5M

[H_2]=\frac{0.50}{1.0}=0.50M

[S_2]=\frac{0.020}{1.0}=0.020M

K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=938450

As the value of K is greater than 1, the reaction is product favored.

2) N_2O_4(g)\rightleftharpoons 2NO_2(g)

K_{eq}=\frac{[NO_2]^2}{[N_2O_4]}

K_{eq}=\frac{[0.500]^2}{[0.0250]}=10

3) N_2+3H_2\rightleftharpoons 2NH_3

K_{eq}=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

4) Reactions which do not continue to completion are called equilibrium reactions as the rate of forward reaction is equal to the rate of backward direction.


3 0
3 years ago
Read 2 more answers
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