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balu736 [363]
3 years ago
8

Help please in picture

Chemistry
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

4 and 6

Explanation:

im not sure tho i dont nw much bout cs

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How is heat transfer by radiation different than transfer by convection or conduction?
nasty-shy [4]

it is B I'm 99% sure it is b

4 0
3 years ago
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In a recent Grand Prix, the winner completed the race with an average speed of 299.8 km/h. What was his speed in miles per hour,
scoundrel [369]

Answer :

(a) The speed is, 186.287 mi/hr

(b) The speed is, 83.277 m/s

(c) The speed is, 273.22 feet/s

Explanation :

(a) We are given the speed is, 299.8km/hr

As we know that,

1km=\frac{1}{1.60934}mi

By using both the conversion, we get:

299.8km/hr

\Rightarrow \frac{299.8km}{1hr}\times \frac{1mi}{1.60934km}

\Rightarrow 186.287mi/hr

The speed is, 186.287 mi/hr

(b) We are given the speed is, 299.8km/hr

As we know that,

1km=1000m

and,

1hr=3600s

By using both the conversion, we get:

299.8km/hr

\Rightarrow \frac{299.8km}{1hr}\times \frac{1000m}{1km}\times \frac{1hr}{3600s}

\Rightarrow 83.277m/s

The speed is, 83.277 m/s

(c) We are given the speed is, 299.8km/hr

As we know that,

1km=3280.84feet

and,

1hr=3600s

By using both the conversion, we get:

299.8km/hr

\Rightarrow \frac{299.8km}{1hr}\times \frac{3280.84feet}{1km}\times \frac{1hr}{3600s}

\Rightarrow 273.22feet/s

The speed is, 273.22 feet/s

3 0
4 years ago
What trend in atomic radius do u see as you go a group family on the periodic table?
exis [7]
Atomic radius increases down a group
7 0
3 years ago
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When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea
Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0
3 years ago
What information do the coefficients of a balanced equation give about the
ale4655 [162]

Answer:

B. The coefficients give the molar ration of the reactants

Explanation:

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3 years ago
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