How many molecules are present in 2.00 mol of KCl?
1 answer:
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Explanation:
The given data is as follows.
Thickness (dx) = 0.87 m, thermal conductivity (k) = 13 W/m-K
Surface area (A) = 5 ,
According to Fourier's law,
Q =
Hence, putting the given values into the above formula as follows.
Q =
=
= 5902.298 W
Therefore, we can conclude that the rate of heat transfer is 5902.298 W.