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Leni [432]
3 years ago
7

Object A at 40.°C and object B at 80.°C are placed in contact with each other. Which statement describes the heat flow between t

he objects?
(1) Heat flows from object A to object B.
(2) Heat flows from object B to object A.
(3) Heat flows in both directions between the objects.
(4) No heat flow occurs between the objects.
Chemistry
2 answers:
alukav5142 [94]3 years ago
5 0

Answer: The correct option is 2.

Explanation: Heat flow is defined as the transfer of energy from hotter object to cooler object when two objects are kept together at different temperatures. As the energy remains conserved, so the heat flow will take place until the equilibrium is attained.

In the above asked question, Object A is at 40° C and Object B is at 80° C.

Object B is at higher temperature, so the heat flow will take place from Object B to Object A.

Hence, the correct option is 2.

Darina [25.2K]3 years ago
4 0

The correct answer is (2) Heat flows from object B to object A


The explanation:


The object B at 80°C and the object A at 40°C so, here object B is higher than


object A at heat and temperature.


and when the heat flow from the object of higher temperature to the lower one and start to lose heat so, the correct answer is (2)

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Explanation:

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A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.
morpeh [17]

Answer:

              Final Temperature = 36.54 ⁰C

Explanation:

Lets suppose the gas is acting ideally, then according to Charle's Law, "<em>The volume of a fixed mass of gas at constant pressure is directly proportional to the absolute temperature</em>". Mathematically for initial and final states the relation is as follow,

                                                V₁ / T₁  =  V₂ / T₂

Data Given;

                  V₁  =  32 L

                  T₁  =  10 °C = 283.15 K             ∴ K = °C + 273.15

                  V₂  =  35 L

                  T₂  =  ??

Solving equation for T₂,

                         T₂  =  V₂ × T₁  / V₁

Putting values,

                         T₂  =  (35 L × 283.15 K) ÷ 32 L

                         T₂  =  309.69 K     ∴ ( 36.54 °C )

Result:

           As the volume is increased from 32 L to 35 L, therefore, the temperature must have increased from 10 °C to 36.54 °C.

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