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Mariana [72]
3 years ago
9

When a central force acts upon an object with a mass of 8kg, the acceleration of the object is 7m/s^2. When the same force acts

upon another object, the acceleration is 4m/s^2. What is the mass of the 2nd object? Please explain why.
Physics
1 answer:
dimulka [17.4K]3 years ago
4 0
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What is the frequency of a wave that has a wavelength of 3m that is traveling at a speed of 9m/s
dezoksy [38]

Answer:

3 m/s

Explanation:

4 0
3 years ago
A transport plane takes off from a level landing field with two gliders in tow, one behind the other. The mass of each glider is
grin007 [14]

Answer:

a) Δx = 180.59 m

b) T = 6001 N

Explanation:

a)

According to Newton's second law, which says that acceleration is directly proportional to the net force, the equation is equal to:

ΣF = m*a = T-f

Clearing a, and solving:

a = (T-f)/m = (T-f)/2*m = (12000-5800)/(2*700) = 4.43 m/s^2

To evaluate the final speed the following equation will be used:

vf^2 = vi^2 + 2*a*Δx = 0 + 2*a*Δx = 2*a*Δx

Clearing Δx:

Δx = vf^2/2*a = (40 m/s)^2/(2* 4.43 m/s^2) = 180.59 m

b)

The tension is equal to:

T = m*a + f = (700 kg * 4.43 m/s^2) + 2900 N = 6001 N

6 0
3 years ago
An object starts at position 12 on a horizontal line with a reference point of 0. What is the position of the object if it moves
Wittaler [7]

-2 is the right answer

8 0
3 years ago
Read 2 more answers
A car speeds past you sounding its horn at a frequency of 1000Hz. The frequency you hear:
ki77a [65]

Answer:

f' =1064.1025 Hz

Explanation:

We know that from doppler's effect

f'=\frac{v+v_0}{v-v_s}f

f'= observed frequency

f= actual frequency =1000 Hz

v= velocity of sound waves = 332 m/s

v_o= velocity of observer =0

v_s= velocity of source. ( let velocity of car be 20 m/s)

therefore,

f'=\frac{332+0}{332-20}\times1000

f' =1064.1025 Hz

3 0
3 years ago
A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and
balandron [24]

The upward force exerted on the board by the support is mathematically given as

Fu= 764.8 N

<h3>What is the upward force exerted on the board by the support?</h3>

Generally, the equation for is  mathematically given as

Considering that the Net Force on the system is null

The weight of the children plus the weight of the board equals the upward force imposed on the support.

The upward force

Fu= 440 + 272 + 52.8 N

Fu= 764.8 N

In conclusion, he upward force exerted on the board by the support

Fu= 764.8 N

Read more about force

brainly.com/question/13191643

#SPJ1

8 0
2 years ago
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