Question

LASTIC OF POTENTIAL ENERGY

Answer 1

Answer:

E = 0.08 J

Explanation:

Given that,

The elastic potential energy of the spring is given by :

$E=\dfrac{1}{2}kx^2$

Where

k is spring constant

x is compression in the spring

We need to find the energy stored when force constant is 400 N-m and the compression is 0.02 m.

$E=\dfrac{1}{2}\times 400\times (0.02)^2\\\\E=0.08\ J$

So, the required energy in the spring is equal to 0.08  J.