<span>7. Colligative properties are directly related to the number of solute particles in a solution
8. chemical formula of sulfuric acid is H2SO4
9. the arhenius base in the choices is LiOH
10. </span><span>A Lewis base is a substance that can donate a pair of electrons
14. basic
15. weak base
</span>
+2 is the oxidation number for Zinc
<span>Oxidation Number for a Transition metal = Number of Unpaired d-electrons + Two s-electrons
</span>[Ar]4s2 3d10 is the electron configuration for zinc. The d-block is full with 10 electrons meaning there are no unpaired d-electrons, so the oxidation number is 0 unpaired d-electrons + 2 s-electrons = +2
Answer:
Stretching is the lengthening and contraction is the shortening
Explanation:
Unless it's asking for eccentric as the stretching and concentric as the shortening
The preparation of lead (ii) sulphate from lead (ii) carbonate occurs in two steps:
- insoluble lead carbonate is converted to soluble lead (ii) nitrate
- soluble lead (ii) nitrate is reacted with sulphuric acid to produce lead (ii) sulphate.
<h3>How can a solid sample of lead (ii) sulphate be prepared from lead (ii) carbonate?</h3>
Lead (ii) carbonate and lead (ii) sulphate are both insoluble salts of lead.
In order to prepare lead (ii) sulphate, a two step process is performed.
In the first step, Lead (ii) carbonate is reacted with dilute trioxonitrate (v) acid to produce lead (ii) nitrate.
- PbCO₃ + 2HNO₃ → Pb(NO₃)₂ + CO₂ + H₂O
In the second step, dilute sulfuric acid is reacted with the lead (ii) nitrate to produce insoluble lead (ii) sulphate which is filtered and dried.
- Pb(NO₃)₂ + H₂SO₄ → PbSO₄ + 2HNO₃
In conclusion, lead (ii) sulphate is prepared in two steps.
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