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Nadusha1986 [10]
2 years ago
7

Which of the following will increase the pressure of a gas in a closed container? I. part of the gas is removed II. the containe

r size is decreased III. temperature is increased
Chemistry
2 answers:
maks197457 [2]2 years ago
7 0
I would go with III. If i’m correct, Brainliest?
Anastasy [175]2 years ago
3 0
There are 2 correct answers I suppose, II and III.

Gas pressure is increased if the molecules inside the container hit the inner wall of the container faster (more frequently), or harder. These are 2 ways of how the gas pressure of some gas is increased. We can figure out if the options will increase the gas pressure. 

For I, removing part of the gas, this will remove part of the gas molecules. In result, fewer molecules will hit the wall because some are removed, like the number density is reduced. This does not increase the gas pressure, but instead decreasing it. So, option I is not correct. 

For II, if the container size is decreased, the gas molecules have a shorter distance to travel before they hit the inner wall of the container, so, they hit the wall faster and more frequently. This can help increase the gas pressure, so option II is correct.

For III, if the temperature of the molecules is increased, the molecules will have a higher kinetic energy. They tend to move faster and of course eventually, they hit the inner wall of the container more frequently. In addition, if they have a higher kinetic energy, they'll even hit the inner wall harder, which can increase the gas pressure too. Therefore, option III is correct too. 

The answer is II and III. 

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How do you determine the chemical reactivity for metals by using the periodic table?
vesna_86 [32]

Answer:

Chemical reactivity increases down a group and decreases from left to right of a period.

Explanation:

The higher the ionization energy is, the lower the reactivity is. Since the ionization energy is highest in the top right corner of the periodic table, we can assume that the most reactive elements are in the opposite bottom left corner. This is because the electrons that react are farther away from the nucleus thus experience less attraction to the nucleus (called nuclear shielding). Therefore their electrons are more easily removed than elements that don't ecperience nuclear shielding.

4 0
3 years ago
Bronze is an example of which of the following:<br><br> element<br> atom<br> solution<br> solvent
Brut [27]
It is a solution, because it's the alloy of tin and copper 
8 0
3 years ago
How much heat must be removed from 25.0g of steam at 118.0C in order to form ice at 15C
NemiM [27]

Answer:

-10778.95 J heat must be removed in order to form the ice at 15 °C.

Explanation:

Given data:

mass of steam = 25 g

Initial temperature = 118 °C

Final temperature = 15 °C

Heat released = ?

Solution:

Formula:

q = m . c . ΔT

we know that specific heat of water is 4.186 J/g.°C

ΔT = final temperature - initial temperature

ΔT = 15 °C - 118 °C

ΔT = -103 °C

now we will put the values in formula

q = m . c . ΔT

q = 25 g × 4.186 J/g.°C × -103 °C

q = -10778.95 J

so, -10778.95 J heat must be removed in order to form the ice at 15 °C.

3 0
3 years ago
Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9
EleoNora [17]

Answer : The current passing between the electrodes is, 1.056\times 10^{-2}A

Explanation :

First we have to calculate the charge of sodium ion.

q=ne

where,

q = charge of sodium ion

n = number of sodium ion = 2.68\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C

Now we have to calculate the charge of chlorine ion.

q'=ne

where,

q' = charge of chlorine ion

n = number of chlorine ion = 3.92\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C

Now we have to calculate the current passing between the electrodes.

I=\frac{q}{t}+\frac{q'}{t}

I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}

I=1.056\times 10^{-2}A

Thus, the current passing between the electrodes is, 1.056\times 10^{-2}A

4 0
2 years ago
which one of the following is an endothermic process?1.ice melting 2.water freezing 3.a boiling soup 4.the reaction of HCl and N
Llana [10]
<span>From the above given choices :
 melting is an endothermic process</span>
8 0
3 years ago
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