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siniylev [52]
3 years ago
8

i dont understand this i cant think :These ions have the same stable electron configuration as the noble gas helium. All Group 1

atoms can lose one electron to form positively charged ions. ... Elements in Groups 15,16 and 17, find it easier to gain electrons than lose them.
Chemistry
2 answers:
Julli [10]3 years ago
7 0

Answer:

Li atoms readily give up one electron to form positively charged, Li+ ions. These ions have the same stable electron configuration as the noble gas helium. All Group 1 atoms can lose one electron to form positively charged ions.

Explanation:

I DON'T KNOW IF THIS IS THE RIGHT ANSWER BUT I'M TRYING TO JUST ANSWER.

noname [10]3 years ago
3 0

Answer:

Explanation:

-We know that an atom is table if they have 8 valence electrons (like noble gases, they are stable)

-Group 1 atoms only has 1 valence electron, in order to become stable, they are desperately wanted to lose that one valence electron to become stable.

-While group 15 has 5 electrons, it is easier for them to gain 3 electrons to become 8 electrons than losing all 5 electrons.

-the same thing for group 16 has 6 valence electrons and 17 has 7 electrons. It is easier for them to gain 2 and 1 more valence electrons to become stable.

Hope this helps!

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Determine the number of grams of carbon dioxide that can be formed from 0.500 grams of iron oxide and an excess of carbon.
Nimfa-mama [501]

Taking into account the reaction stoichiometry, 0.2066 grams of CO₂ are formed from 0.500 grams of iron oxide and an excess of carbon.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 Fe₂O₃ + 3 C → 4 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Fe₂O₃: 2 moles
  • C: 3 moles
  • Fe:4 moles
  • CO₂: 3 moles

The molar mass of the compounds is:

  • Fe₂O₃: 159.7 g/mole
  • C: 12 g/mole
  • Fe: 55.85 g/mole
  • CO₂: 44 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Fe₂O₃: 2 moles ×159.7 g/mole= 319.4 grams
  • C: 3 moles ×12 g/mole= 36 grams
  • Fe: 4 moles ×55.85 g/mole= 223.4 grams
  • CO₂: 3 moles ×44 g/mole= 132 grams

<h3>Mass of CO₂ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 319.4 grams of Fe₂O₃ form 132 grams of CO₂, 0.500 grams of Fe₂O₃ form how much mass of CO₂?

mass of CO_{2} =\frac{0.500 grams of Fe_{2}O_{3}x132 grams of CO_{2} }{319.4 grams of Fe_{2}O_{3}}

<u><em>mass of CO₂= 0.2066 grams</em></u>

Then, 0.2066 grams of CO₂ are formed from 0.500 grams of iron oxide and an excess of carbon.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

7 0
2 years ago
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